Symfony2 Twig 获取子实体的总数 [英] Symfony2 Twig Get Total Count for Child Entity
问题描述
存在以下实体:农场、谷仓和动物.一个农场可以有很多谷仓,一个谷仓可以有很多动物.
The following entities exist, Farm, Barn and Animals. A Farm can have many Barns and a Barn many Animals.
在 TWIG 模板中显示农场时,还应显示动物数量.
When displaying a Farm in a TWIG template the number of Animals should be shown as well.
最好的方法是什么?
我创建了一个 TWIG 扩展,它可以让我轻松显示谷仓的数量.
I have create a TWIG extension which allows me to easily show the number of barns.
public function totalFieldFilter($data, $getField='getTotal') {
$total = count($data->$getField());
return $total;
}
在我的模板中,我将使用 {{ farm|totalField('getBarns') }},我可以轻松地扩展它来编写另一个自定义函数,如下所示:
In my template I would use {{ farm|totalField('getBarns') }}, I could easily extend this to write another custom function like so:
public function totalFieldFilter($farm) {
$total = 0;
foreach($farm->getBarns() AS $barn) {
$total += count($barn->getAniamls());
}
return $total;
}
虽然这行得通,但有没有更好的方法,可以使其更通用吗?如果我想计算动物的腿怎么办?或者一个谷仓有多少扇门,我每次都必须编写一个自定义的 TWIG 扩展.
Although this would work, is there a better way and can it be made more generic? What if I wanted to count Legs on Animals? Or how many Doors a Barn has, I would have to write a custom TWIG extension each time.
推荐答案
使用实体访问器 :
{% for farm in farms %}
{{ farm.name }}
{% set barns = farm.getBarns() %}
Barns count = {{ barns|length }}
{% for barn in barns %}
{% set animals = barn.getAnimals() %}
{{ barn.name }} animals count : {{ animals|length }}
{% endfor %}
{% endfor %}
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