Twitter4j:搜索公共推文 [英] Twitter4j : Search for public tweets
本文介绍了Twitter4j:搜索公共推文的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
如何使用 Twitter4j 库在公共推文中进行搜索?
How does one search within public tweets using the Twitter4j library ?
public static void main(String[] args) {
Twitter twitter = new TwitterFactory().getInstance();
try {
Query query = new Query("Cocaine");
QueryResult result;
do {
result = twitter.search(query);
List<Status> tweets = result.getTweets();
for (Status tweet : tweets) {
System.out.println("@" + tweet.getUser().getScreenName() + " - " + tweet.getText());
}
} while ((query = result.nextQuery()) != null);
System.exit(0);
} catch (TwitterException te) {
te.printStackTrace();
System.out.println("Failed to search tweets: " + te.getMessage());
System.exit(-1);
}
}
这给了我一个身份验证凭据丢失.
错误
推荐答案
您需要为 Twitter 注册您的应用.如果您拥有自己的私人帐户,则只能这样做.在您获得 ConsumerKey
、ConsumerSecret
、AccessToken
和 AccessTokenSecret
后(它们会在您注册应用程序后呈现给您)),最简单的解决办法就是把代码改成下面的例子:
You need to register your app for Twitter. You can only do that if you have your own private account. After you obtain ConsumerKey
, ConsumerSecret
, AccessToken
and AccessTokenSecret
(they will be presented to you afret you register your application), the simplest solution is to change the code to the following example:
public static void main(String[] args) {
ConfigurationBuilder cb = new ConfigurationBuilder();
cb.setDebugEnabled(true)
.setOAuthConsumerKey("yourConsumeKey")
.setOAuthConsumerSecret("yourConsumerSecret")
.setOAuthAccessToken("yourAccessToken")
.setOAuthAccessTokenSecret("yourTokenSecret");
TwitterFactory tf = new TwitterFactory(cb.build());
Twitter twitter = tf.getInstance();
try {
Query query = new Query("query");
QueryResult result;
result = twitter.search(query);
List<Status> tweets = result.getTweets();
for (Status tweet : tweets) {
System.out.println("@" + tweet.getUser().getScreenName() + " - " + tweet.getText());
}
System.exit(0);
} catch (TwitterException te) {
te.printStackTrace();
System.out.println("Failed to search tweets: " + te.getMessage());
System.exit(-1);
}
}
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