你如何转换 UnsafeMutablePointer<Void>到UInt8? [英] How do you convert a UnsafeMutablePointer&lt;Void&gt; to UInt8?

问题描述

这个问题真的很简单，但不知何故我不知道该怎么做:

The question is really simple, but somehow I don't know how to do it:

如何将 UnsafeMutablePointer 转换为 UInt8?

How do you convert a UnsafeMutablePointer to UInt8?

我尝试像这样转换它:

UInt8(theUnsafeMutablePointerVar)

但它给了我以下错误:找不到接受类型为UnsafeMutablePointer"的参数列表的UInt8"类型的初始值设定项

推荐答案

你必须先把指针转换成正确的类型(一个指向 UInt8 的指针)然后你可以访问它指向的内存:

You have to convert the pointer to the correct type first (a pointer to UInt8) and then you can access the memory it points to:

let u8 = UnsafePointer<UInt8>(theUnsafeMutablePointerVar).memory

在 Swift 3 中， 一个来自 C 的空指针被导入到 Swift 作为UnsafeMutableRawPointer，可以读取指向的数据与

In Swift 3, a void pointer from C is imported to Swift as UnsafeMutableRawPointer, and one can read the pointed-to data with

let u8 = theUnsafeMutablePointerVar.load(as: UInt8.self)

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