将动态变量转换为 List<model>或数组 [英] Converting a dynamic Variable to List&lt;model&gt; or array

问题描述

我想将这个带有 Ajax 的数组发送到 api :

I want to send this Array with Ajax to api :

var receipt = Array();

        receipt = [
            { 'Service': 'Saab', 'Order': '20' },
            { 'Service': 'Volvo', 'Order': '12' },
            { 'Service': 'BMW', 'Order': '25' }
        ];

这是我的 Ajax 主体:

And this is my Ajax body :

var r = JSON.stringify(receipt);
        
        $.ajax({
            type: "POST",
            dataType: "Json",
            contentType: "application/json; charset=utf-8",
            data: r,
            url: "api/Receipt",
            success: function (result) {
                // To Do
                console.info(result);
            },
            error: function (result) {
                console.info(result);
            }
        });

这就是我作为 Json 得到的:

And this is what i get as Json :

        {[
            {
               "Service": "Saab",
               "Order": "20"
            },
            {
               "Service": "Volvo",
               "Order": "12"
             },
             {
               "Service": "BMW",
               "Order": "25"
              }
          ]}

我在 api 端捕捉它们就像这样:

And i catch them in api side Like this :

[Route("api/Receipt")]
    [WebMethod]
    public string Receipt_Turn(object obj)
    {
        dynamic dyn = JsonConvert.DeserializeObject(obj.ToString());

        if (dyn != null)
        {
            return dyn[1].ToString();
        }
        else
        {
            return "false";
        }

    }

它可以工作，return dyn[1].ToString() 部分返回我的数组的第二条记录.但我想将此动态变量转换为模型的列表或数组.

And it works, the part return dyn[1].ToString() returns second record of my Array. But i want to convert this dynamic variable to a list or array of a model .

这是我的模型:

[Serializable()]
    public class Receipt
    {
        public string Service { get; set; }
        public string Order { get; set; }
    }

我想这样做:

string serv = receipt[1].Service;

我该怎么做?

谢谢...

推荐答案

删除 JS 脚本中的数组部分并像这样编写:

Delete the Array Part in Your JS Script and Write it Like this :

var receipt = [
            { 'Service': 'Saab', 'Order': '20' },
            { 'Service': 'Volvo', 'Order': '12' },
            { 'Service': 'BMW', 'Order': '25' }
        ];

在这种形状中，您正在发送一个对象.在你的代码中，我猜你正在发送一个 JArray 所以它会在从 JArray 转换为另一种类型时产生一些问题.

in this shape you are sending an Object. in your code i guess you are sending an JArray So it Will make some Problems in Converting from JArray to another Type .

在您的 API 端，编辑您的代码如下:

in your API Side , Edit Your Code As Below :

public string Receipt_Turn(object r)
    {

        //important Line Here
        List<Receipt> rr = JsonConvert.DeserializeObject<List<Receipt>>(r.ToString());

        if (rr != null)
        {
            return rr[1].ToString();
        }
        else
        {
            return "false";
        }

    }

如您所见，我们像对象一样获取它，然后我们将能够像我提到的那样准备您的 DeserializeObject 部分.

as you can see, we get it Like an Object and then we will be able to Get Ready your DeserializeObject part Like i mentioned.

你最需要声明你的模型列表，然后在 DeserializeObject 部分之后添加你想要将它转换为的类型.

you most declare a List of your Model, and after part DeserializeObject add that Type You want to Convert it to.

这里因为我们声明了 List ，我们应该将我们的 DeserializeObject 转换成它，所以我们添加 >DeserializeObject 之后的代码>.

here Cause we Declared List<Receipt> , we should convert our DeserializeObject to it, so we add <List<Receipt>> after DeserializeObject.

最后你可以随心所欲地使用它.

and Finally you can use it Like You wish .

string serv = rr[1].Service;

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