在 Swift 中将字节数组转换为双精度 [英] Convert byte array to double in Swift

问题描述

如何在 Swift 中将字节数组转换为双精度值?

How can one convert an array of bytes into a double value in Swift?

(这是一个 NSInputStream 扩展)

(It's an NSInputStream extension)

我的代码片段附在下面，但它没有返回正确的双精度值:

My snippet attached below, but it's not returning correct double value:

func readDouble() -> Double
{
var readBuffer = Array<UInt8>(count:sizeof(Double), repeatedValue: 0)

        let numberOfBytesRead = self.read(&readBuffer, maxLength: readBuffer.count)
        let help1 = Int(readBuffer[0] & 0xff) << 56 | Int(readBuffer[1] & 0xff) << 48
        let help2 = Int(readBuffer[2] & 0xff) << 40 | Int(readBuffer[3] & 0xff) << 32
        let help3 = Int(readBuffer[4] & 0xff) << 24 | Int(readBuffer[5] & 0xff) << 16
        let help4 = (Int(readBuffer[6] & 0xff) << 8) | Int(readBuffer[7] & 0xff)
        return Double(help1 | help2 | help3 | help4)
}

推荐答案

很简单:

extension FloatingPoint {

    init?(_ bytes: [UInt8]) {

        guard bytes.count == MemoryLayout<Self>.size else { return nil }

        self = bytes.withUnsafeBytes {

            return $0.load(fromByteOffset: 0, as: Self.self)
        }
    }
}

let array: [UInt8] =  [0, 0, 0, 0, 0, 0, 240, 63]
let num = Double(array) // 1.0

此代码适用于 Swift 中的任何浮点类型.

This code does work for any floating point type in Swift.

ma​​cOS 上的 Swift 3.0(little-endian 表示 Double)

您可以在此处查找我的备忘单以进行字节转换.(小/大端数字转换)

You can look up my cheat sheet for byte conversion here. (little/big endian number conversion)

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