我如何替换另一个值变化的阵列? [英] How do I replace a changing array with another value?
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问题描述
我有个约会数组,它包含当前日加10天,我从导入数据库的数组。我也有一个动物名数组。基于什么是进口的我要放置动物名在筛选阵列中的过滤阵列。例如:
日期数组:`[9,10,11,12,13,14,15,16,17,18]`
进口日期数组从DB:[9,12,14,18]
从数据库进口的动物名称数组:狗,猫,虎,羊]
这就是我想要过滤的动物名看起来像
过滤动物名数组:[狗,,猫,虎,,,羊]
我知道我所提供的code是错的,我觉得我incorretly接近这一。我应该怎么做呢?
为(VAR J = 0; J< self.arrayofweek.count; J ++){
对于(VAR T = 0; T< self.datesfromdb.count;吨++){
如果(self.date [T] == self.datearray [J]){
self.namefiltered [T] = self.tutorname [J]。
打印(过滤名\\(self.namefiltered))
}
}
}
解决方案
数据:
让日期= [9,10,11,12,13,14,15,16,17,18]
让进口= [9,12,14,18]
让动物= [狗,猫,虎,羊]
重做:
让过滤= {dates.map拉链(进口,动物).MAP {$ 0.0次} .indexOf($ 0){.MAP动物[$ 0]}? }
输出:
打印(阵列)// [狗,,,猫,,虎,,,,羊]
基于FranMowinckel的回答
,但100%的安全。
I have a date array which contains the current day plus 10 days, and I am importing an array from a database. I also have an animal name array. Based on what is imported I want to place the animal name in a filtered array in a filtered array. For example:
date array: `[9, 10, 11, 12, 13, 14, 15, 16, 17, 18]`
imported date array from db: [9, 12, 14, 18]
imported animal name array from db: [dog, cat, tiger, sheep]
This is what I want the filtered animal name to look like
filtered animal name array: [dog, "", "", cat, "", tiger, "", "", "", sheep]
I know the code I provided is wrong, I feel I am approaching this incorretly. How should I do this?
for(var j = 0; j < self.arrayofweek.count; j++){
for(var t = 0; t < self.datesfromdb.count; t++){
if(self.date[t] == self.datearray[j]){
self.namefiltered[t] = self.tutorname[j]
print("filtered name \(self.namefiltered)")
}
}
}
解决方案
Data:
let dates = [9, 10, 11, 12, 13, 14, 15, 16, 17, 18]
let imported = [9, 12, 14, 18]
let animals = ["dog", "cat", "tiger", "sheep"]
Reworked:
let filtered = dates.map { zip(imported, animals).map { $0.0 }.indexOf($0).map { animals[$0] } ?? "" }
Output:
print(array) // ["dog", "", "", "cat", "", "tiger", "", "", "", "sheep"]
Based on FranMowinckel's answer, but 100% safe.
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