JSONObject的阵中的一些Android的数据返回null [英] JSONObject Array returns null for some of the data in android
问题描述
我得到使用JSON问题到Android。出于某种原因，一些数据时，我收到使用JSONObject.getInt方法，它会返回一些数据空的。不是所有的数据我收到返回null好像只返回null是一个整数，我有其他的整型数据和他们收到它只是罚款，没有它曾经被空的数据类型。它似乎是只用整数变量的3相一致。我读过这个，因为它是作为一个错误的地方，但我不知道是否这就是这种情况。顺便说一下我使用的Android乱射。
对此有更好的办法？
StringRequest strReq =新StringRequest（Request.Method.POST，
AppConfig.URL_LOGIN，新Response.Listener＆LT;串GT;（）{ @覆盖
公共无效onResponse（字符串响应）{
Log.d（TAG，登录响应：+ response.toString（））;
hideDialog（）; 尝试{
JSONObject的jObj =新的JSONObject（响应）;
布尔误差= jObj.getBoolean（错误）; //检查以JSON错误节点
如果（！错误）{
//用户成功登录
//创建登录会话
session.setLogin（真）; 字符串的uid = jObj.getString（UID）; JSONObject的用户= jObj.getJSONObject（用户）;
...（返回精其他变量）
INT activitylvl = user.getInt（activitylvl）; //获取空
INT meal_plan = user.getInt（meal_plan）; //获取空
INT workout_plan = user.getInt（workout_plan）; //获取空
继续.....};
编辑：
我的继承人结果我的反应
{
错误：假的，
UID：56551efd883b55.31836995，
用户：{
名：测试，
电子邮件：test@gmail.com
目标：1
图片： ，
性别：M，
生日：1993年8月6日，
height_cm：182，
height_ft：6，
height_in：0，
weight_kg：74
weight_lbs：165，
activitylvl：空，
卡路里：2861.43，
meal_plan：空，
workout_plan：空，
adjust_calories_wd：0，
adjust_calories_nwd：0，
workout_week：假的，假的，假的，假的，假的，假的，假的，
created_at：2015年11月24日21时37分49秒，
的updated_at：2015年11月24日21时37分49秒
}
}
PHP
//获得通过电子邮件和密码的用户
$ USER = $ DB-GT＆; getUserByEmailAndPassword（$电子邮件，$密码）;如果（$用户！= FALSE）{
//使用被发现
$响应[错误] = FALSE;
$响应[UID] = $用户[UNIQUE_ID];
$响应[用户] [名称] = $用户[名];
$响应[用户] [电子邮件] = $用户[电子邮件];
$响应[用户] [目标] = $用户[目标];
$响应[用户] [形象] = $用户[形象];
$响应[用户] [性别] = $用户[性别];
$响应[用户] [生日] = $用户[生日];
$响应[用户] [height_cm] = $用户[height_cm];
$响应[用户] [height_ft] = $用户[height_ft];
$响应[用户] [height_in] = $用户[height_in];
$响应[用户] [weight_kg] = $用户[weight_kg];
$响应[用户] [weight_lbs] = $用户[weight_lbs];
$响应[用户] [activitylvl] = $用户[activitylvl];
$响应[用户] [卡路里] = $用户[卡路里];
$响应[用户] [meal_plan] = $用户[meal_plan];
$响应[用户] [workout_plan] = $用户[workout_plan];
$响应[用户] [adjust_calories_wd] = $用户[adjust_calories_wd];
$响应[用户] [adjust_calories_nwd] = $用户[adjust_calories_nwd];
$响应[用户] [workout_week] = $用户[workout_week];
$响应[用户] [created_at] = $用户[created_at];
$响应[用户] [的updated_at] = $用户[的updated_at];
回声json_en code（$响应）;
}其他{
//用户没有使用凭据找到
$响应[错误] = TRUE;
$响应[ERROR_MSG] =登录凭据错误，请重试！
回声json_en code（$响应）;
}公共职能getUserByEmailAndPassword（$电子邮件，$密码）{
//做到这一点，为用户数据库以及
$结果= mysqli_query（$这个 - ＆GT;康涅狄格州，SELECT * FROM用户WHERE电子邮件= $电子邮件'）或死亡（mysqli_connect_errno（））; //检查结果
$ no_of_rows = mysqli_num_rows（$结果）; 如果（$ no_of_rows大于0）{
$结果= mysqli_fetch_array（$结果）;
$盐= $结果['盐'];
$ encrypted_password = $结果['encrypted_password'];
$哈希= $这个 - ＆GT; checkhashSSHA（$盐，$密码）; //检查密码
如果（$ encrypted_password == $哈希）{
返回$结果;
} }其他{
返回false;
}}
我琢磨出来的问题是与用户响应名，这是一个PHP的问题：
getUserByEmailAndPassword的功能里面有一个方法
名为
mysqli_fetch_array（mysqli_query）;
这抓起列名，并将其与作为mysql数据库列名我错了名字的键名的数组。
错误的。
$回应[用户] [activitylvl] = $用户[activitylvl];
$回应[用户] [meal_plan] = $用户[meal_plan];
$回应[用户] [workout_plan] = $用户[workout_plan];
正确
$回应[用户] [activitylvl] = $用户[活动];
$回应[用户] [meal_plan] = $用户[mealplan];
$回应[用户] [workout_plan] = $用户[workoutplan];
I'm getting problems with JSON to Android. For some reason some of the data when i receive it using JSONObject.getInt method it returns some of the data null. Not all the data i receive returns null it seems like only the Data type that returns null is Integers and i have other Integer data and they receive it just fine without it ever being null. It seems to be consistent with only 3 of the integer variables. I've read this as it being being a bug somewhere but I don't know for sure if thats the case. By the way i'm using Android Volley.
Is there a better way for this?
StringRequest strReq = new StringRequest(Request.Method.POST, AppConfig.URL_LOGIN, new Response.Listener<String>() { @Override public void onResponse(String response) { Log.d(TAG, "Login Response: " + response.toString()); hideDialog(); try { JSONObject jObj = new JSONObject(response); boolean error = jObj.getBoolean("error"); // Check for error node in json if (!error) { // user successfully logged in // Create login session session.setLogin(true); String uid = jObj.getString("uid"); JSONObject user = jObj.getJSONObject("user"); ...(OTHER Variables that return fine) int activitylvl = user.getInt("activitylvl");//get null int meal_plan = user.getInt("meal_plan");//get null int workout_plan = user.getInt("workout_plan");//get null Continues.....};EDITS: Heres my result to my response
{ "error": false, "uid": "56551efd883b55.31836995", "user": { "name": "Test", "email": "test@gmail.com", "goal": "1", "image": "", "gender": "M", "birthdate": "8/6/1993", "height_cm": "182", "height_ft": "6", "height_in": "0", "weight_kg": "74", "weight_lbs": "165", "activitylvl": null, "calories": "2861.43", "meal_plan": null, "workout_plan": null, "adjust_calories_wd": "0", "adjust_calories_nwd": "0", "workout_week": "false, false, false, false, false, false, false", "created_at": "2015-11-24 21:37:49", "updated_at": "2015-11-24 21:37:49" } }PHP
// get the user by email and password $user = $db->getUserByEmailAndPassword($email, $password); if ($user != false) { // use is found $response["error"] = FALSE; $response["uid"] = $user["unique_id"]; $response["user"]["name"] = $user["name"]; $response["user"]["email"] = $user["email"]; $response["user"]["goal"] = $user["goal"]; $response["user"]["image"] = $user["image"]; $response["user"]["gender"] = $user["gender"]; $response["user"]["birthdate"] = $user["birthdate"]; $response["user"]["height_cm"] = $user["height_cm"]; $response["user"]["height_ft"] = $user["height_ft"]; $response["user"]["height_in"] = $user["height_in"]; $response["user"]["weight_kg"] = $user["weight_kg"]; $response["user"]["weight_lbs"] = $user["weight_lbs"]; $response["user"]["activitylvl"] = $user["activitylvl"]; $response["user"]["calories"] = $user["calories"]; $response["user"]["meal_plan"] = $user["meal_plan"]; $response["user"]["workout_plan"] = $user["workout_plan"]; $response["user"]["adjust_calories_wd"] = $user["adjust_calories_wd"]; $response["user"]["adjust_calories_nwd"] = $user["adjust_calories_nwd"]; $response["user"]["workout_week"] = $user["workout_week"]; $response["user"]["created_at"] = $user["created_at"]; $response["user"]["updated_at"] = $user["updated_at"]; echo json_encode($response); } else { // user is not found with the credentials $response["error"] = TRUE; $response["error_msg"] = "Login credentials are wrong. Please try again!"; echo json_encode($response); } public function getUserByEmailAndPassword($email, $password) { //DO this for users db as well $result = mysqli_query($this->conn,"SELECT * FROM users WHERE email = '$email'") or die(mysqli_connect_errno()); // check for result $no_of_rows = mysqli_num_rows($result); if ($no_of_rows > 0) { $result = mysqli_fetch_array($result); $salt = $result['salt']; $encrypted_password = $result['encrypted_password']; $hash = $this->checkhashSSHA($salt, $password); // check for password if ($encrypted_password == $hash) { return $result; } } else { return false; } }
解决方案I figured it out the problem was with the user response name it was a php problem:
inside the function of getUserByEmailAndPassword there is a method called
mysqli_fetch_array(mysqli_query);
this grabs the column name and sets it in an array with the key name as the column name in mysql database I had the wrong name.
INCORRECT
$response["user"]["activitylvl"] = $user["activitylvl"];
$response["user"]["meal_plan"] = $user["meal_plan"];
$response["user"]["workout_plan"] = $user["workout_plan"];
CORRECT
$response["user"]["activitylvl"] = $user["activity"];
$response["user"]["meal_plan"] = $user["mealplan"];
$response["user"]["workout_plan"] = $user["workoutplan"];
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