如何禁用按钮边界外的TouchUpInside Action [英] How to disable TouchUpInside Action outside the boundary of button
问题描述
这是我的 Xib.我只是拖了一个 UIButton 并改变了它的背景颜色.
This is my Xib. I just dragged a UIButton and changed its background color.
我使用此代码创建了一个半圆形图层
I created a semi circle layer using this code
let circlePath = UIBezierPath.init(arcCenter: CGPointMake(mybutton.bounds.size.width / 4, 0), radius: mybutton.bounds.size.height, startAngle: 0.0, endAngle: CGFloat(M_PI), clockwise: true)
let circleShape = CAShapeLayer()
circleShape.path = circlePath.CGPath
mybutton.layer.mask = circleShape
这是我的输出.
它是我想要的完美.但问题是此按钮可在其圆形区域外单击(根据按钮的实际形状).我希望它只能作为圆形点击.
Its perfect as I want it. But the problem is that this button is clickable outside its rounded area(as per actuall shape of button). I want it to be clickable only as rounded shape.
我怎样才能做到这一点?谢谢.
How can I achieve this ? Thanks.
推荐答案
创建签名动作
- (IBAction)buttonPressed:(id)sender forEvent:(UIEvent*)event{
//your code
}
用于您的按钮
使用此答案找出触摸位置UIButton TouchUpInside Touch Location
Find out touch location using this answer UIButton TouchUpInside Touch Location
使用
- (IBAction)buttonPressed:(id)sender forEvent:(UIEvent*)event{
//find location point using above answer link
if([button.layer.mask containsPoint: location])
{
//proceed with the code
}
}
如果它包含点,则返回一个布尔值.
it returns a bool if it contains point.
即如果它包含点,您可以继续,否则您可以返回.
i.e if it contains point you can proceed otherwise you can return.
希望有帮助:)
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