iOS - UIButton 成为打开键盘的第一响应者 [英] iOS - UIButton become first responder to open keyboard

问题描述

我需要在单击按钮时为 UIButton 打开键盘(不使用/用于 UITextField).我试图通过覆盖变量 canBecomeFirstResponder 来创建自定义按钮，但它不起作用.

I need to open keyboard on button click for UIButton (not using/for UITextField). I have tried to create custom button by overriding variable canBecomeFirstResponder but it's not working.

还有其他方法吗?

注意:我想设置UIPIckerView作为UIButton在keyboard frame的输入视图.

Note: I want to set UIPIckerView as an input view of UIButton in key board frame.

这是我的代码.

class RespondingButton: UIButton {


    override var canBecomeFirstResponder: Bool {
        return true
    }


    override init(frame: CGRect) {
        super.init(frame: frame)
        commonInit()
    }


    required init?(coder aDecoder: NSCoder) {
        super.init(coder: aDecoder)
        commonInit()
    }


    private func commonInit() {
        // common init
    }



}

在我的视图控制器中，我连接了按钮操作.

In my view controller, I connected button action.

class TestViewController: UIViewController {

   @IBAction func testBecomeFirstResponder(button: RespondingButton){
      button.becomeFirstResponder()  // Not working.
   } 
}

推荐答案

像这样添加对 UIKeyInput 的一致性.它应该工作.

Add conformance to UIKeyInput like this. It should work.

class RespondingButton: UIButton, UIKeyInput {

    override var canBecomeFirstResponder: Bool {
        return true
    }

    var hasText: Bool = true
    func insertText(_ text: String) {}
    func deleteBackward() {}
}

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