裸字符串数组等效 [英] Array Equivalent of Bare-String

问题描述

我可以这样做没有问题：

I can do this without issue:

const char* foo = "This is a bare-string";

我要的是能够做同样的事情用一个数组：

What I want is to be able to do the same thing with an array:

const int* bar = {1, 2, 3};

显然，这code不编译，但有一些类型的数组相当于裸字符串？

Obviously that code doesn't compile, but is there some kind of array equivalent to the bare-string?

推荐答案

您不能做到这一点：

const int* bar = {1, 2, 3};

但你可以这样做：

But you can do this:

const int bar[] = {1, 2, 3};

原因是C（或C ++）有一个附加的功能，除了作为一个字符指针工作，它也可以作为一个C字符串，从而增加初始化方法（特别对于char *）的字符*：

Reason is that char* in C (or C++) have an added functionality, besides working as a char pointer, it also works as a "C string", thus the added initialization method (special for char*):

const char* foo = "This is bare-string";

最好的。

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