有什么不对的,而循环? [英] Is something wrong in the while loop?

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问题描述

我有一个store_credits_orders表

I have a store_credits_orders table

和订单表。

这是我想要的输出与此类似,但根据店铺信用秩序的日期和时间商店订购日期和时间

The output that I want is similar to this but based on Store Credit Order Date and Time and Store Order Date and Time:

在code,我到目前为止已经试过:

The code that I have tried so far:

<?php
$table = '';
$queryToGetStoreCredit = "SELECT * FROM store_credits_orders WHERE SCO_CustEmailAdd = '".$_SESSION["Customer"]["email"]."'";
$validate->Query($queryToGetStoreCredit);
if ($validate->NumRows() >= 1) {
    while ($rows_sco = $validate->FetchAllDatas()) {
        $used = $i = 0;
        $table .= '<tr>';
        $table .= '<td>'.$rows_sco["SCO_OrderCode"].'</td>';
        $table .= '<td>--</td>';
        $table .= '<td>'.$rows_sco["SCO_OrderDate"].'</td>';
        $table .= '<td>--</td>';
        $table .= '<td>'.$rows_sco["SCO_Purchase_Amount"].'</td>';
        $table .= '<td>'.$rows_sco["SCO_Credit_Alloted"].'</td>';
        $table .= '<td>'.$used.'</td>';
        $table .= '<td>'.( $rows_sco["SCO_Credit_Alloted"] - $used ).'</td>';
        $table .= '</tr>';

        $validate2 = new Validation();
        $queryToGetOrder = "SELECT * FROM orders WHERE CustEmailAdd = '".$rows_sco["SCO_CustEmailAdd"]."'";
        $validate2->Query($queryToGetOrder);
        while ($row = $validate2->FetchAllDatas()) {
            $table .= '<tr>';
            $table .= '<td>--</td>';
            $table .= '<td>'.$row["OrderCode"].'</td>';
            $table .= '<td>--</td>';
            $table .= '<td>'.$row["OrderDate"].'</td>';
            $table .= '<td>--</td>';
            $table .= '<td>--</td>';
            $table .= '<td>'.$row["AppliedCredits"].'</td>';
            $table .= '<td>'.($rows_sco["SCO_Credit_Alloted"] - $row["AppliedCredits"]).'</td>';
            $table .= '</tr>';
        }
    }
}
?>

我想实现的是,每当有购买store_credits,信息将被插入在 store_credits_orders 表。现在,当同一个用户来了,下单和赎回store_credits(大于等于,他在他的帐户具有更低),将有比在插入订单表中的其他数据库没有更新。

What I want to achieve is, whenever there is a purchase of store_credits, the information will get inserted in the store_credits_orders table. Now when the same user comes, places an order and redeems the store_credits (less than equal to, he has in his account), there will be no update in the database other than insertion in the orders table.

但是,当用户登录时,他应该能够看到,当他已经购买了store_credits和/或当他赎回store_credits。所有这些活动应该由哪个事件发生第一次下令,不论购买或赎回。

But when the user logs in, he should be able to see when he has purchased the store_credits and/or when he has redeemed the store_credits. All these events should be ordered by whichever event happens first, irrespective of purchase or redeem.

推荐答案

我跟@ user3514160,我得到了清晰,他想的有什么。数据基本上被正确插入。只有他想的是按照正确的方式来显示数据。

I talked to @user3514160 and I got clarity what he want's to have. Basically data gets inserted correctly. Only thing he wants is to show data in correct way.

您的查询应该是这样的。

(SELECT
  SCO_Id,
  SCO_OrderCode,
  SCO_CustEmailAdd,
  SCO_Purchase_Amount,
  SCO_Credit_Alloted,
  SCO_OrderDate,
  SCO_OrderIP,
  null AS OrderId,
  null AS OrderCode,
  null AS CustEmailAdd,
  null AS AppliedCredits,
  null AS OrderDate,
  'store_credits_orders' AS tableName
FROM `store_credits_orders` AS credits_orders WHERE `SCO_CustEmailAdd` = '".$_SESSION["Customer"]["email"]."')
UNION
(SELECT
  OrderId,
  OrderCode,
  CustEmailAdd,
  AppliedCredits,
  OrderDate
  null AS SCO_Id,
  null AS SCO_OrderCode,
  null AS SCO_CustEmailAdd,
  null AS SCO_Purchase_Amount,
  null AS SCO_Credit_Alloted,
  OrderDate AS SCO_OrderDate,
  null AS SCO_OrderIP,
  'store_orders' AS tableName
FROM `store_orders` AS orders WHERE `SCO_CustEmailAdd` = '".$_SESSION["Customer"]["email"]."')
ORDER BY `SCO_OrderDate` ASC

这是需要得到一个结果的所有行。我们做到这一点与 MySQL的UNION

This is needed to get all rows in one result. We accomplish this with MySQL UNION.

UNION需要两个表有有相同的名字列相同。这就是为什么我们添加空列与 NULL作为COLUMNNAME

UNION needs both tables to have same amount of columns with same names. This is why we add empty columns with null AS columnName.

PHP 与查询

<?php
$table = '<table>';

// Query to get all rows from both tables
$queryToGetStoreCredit = 
"(SELECT
  SCO_Id,
  SCO_OrderCode,
  SCO_CustEmailAdd,
  SCO_Purchase_Amount,
  SCO_Credit_Alloted,
  SCO_OrderDate,
  SCO_OrderIP,
  null AS OrderId,
  null AS OrderCode,
  null AS CustEmailAdd,
  null AS AppliedCredits,
  null AS OrderDate,
  'store_credits_orders' AS tableName
FROM `store_credits_orders` AS credits_orders WHERE `SCO_CustEmailAdd` = '".$_SESSION["Customer"]["email"]."')
UNION
(SELECT
  OrderId,
  OrderCode,
  CustEmailAdd,
  AppliedCredits,
  OrderDate
  null AS SCO_Id,
  null AS SCO_OrderCode,
  null AS SCO_CustEmailAdd,
  null AS SCO_Purchase_Amount,
  null AS SCO_Credit_Alloted,
  OrderDate AS SCO_OrderDate,
  null AS SCO_OrderIP,
  'store_orders' AS tableName
FROM `store_orders` AS orders WHERE `SCO_CustEmailAdd` = '".$_SESSION["Customer"]["email"]."')
ORDER BY `SCO_OrderDate` ASC";

$validate->Query($queryToGetStoreCredit);
if ($validate->NumRows() >= 1) {
    // Starting balance. This could be some other number, for example if viewing some certain period of orders etc.
    $balance = 0;
    while ($row = $validate->FetchAllDatas()) {

        // Add to balance
        if($row['tableName'] == 'store_credits_orders' && (int)$row['SCO_Credit_Alloted'] > 0){
          $balance += (int)$row['SCO_Credit_Alloted']
        }
        // Remove from balance
        else if($row['tableName'] == 'store_orders' && (int)$row['AppliedCredits'] > 0){
          $balance -= (int)$row['AppliedCredits'];
        }

        $table .= '<tr>';
        $table .= '<td>'.$row["SCO_OrderCode"].'</td>';
        $table .= '<td>'.$row["OrderCode"].'</td>';
        $table .= '<td>'.(($row['tableName'] == 'store_credits_orders') ? $row["SCO_OrderDate"] : '').'</td>';
        $table .= '<td>'.$row["OrderDate"].'</td>';
        $table .= '<td>'.$row["SCO_Purchase_Amount"].'</td>';
        $table .= '<td>'.$row["SCO_Credit_Alloted"].'</td>';
        $table .= '<td>'.$row["AppliedCredits"].'</td>';
        $table .= '<td>'.$balance.'</td>';
        $table .= '</tr>';
    }
}

$table .= '</table>';

echo $table;
?>

让我知道,如果有一些问题。

Let me know, if there is some problems.

这篇关于有什么不对的,而循环?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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