伯爵在PHP数组一组数组数 [英] Count number of a group array in array in php

问题描述

我要计数阵列中的一组阵列的数目。示例

  $ ARR1 = [61,41,41,61,89,90]
$ ARR2 = [61,41]
$结果= 2 //发现61,41在$ ARR1 2次;
 

或示例

  $ ARR1 = [89,61,41,41,61,90]
$ ARR2 = [61,41,89]
$结果= 1 //发现61,41,89在$ ARR1 1次;
 

该怎么写code或概念？

解决方案

我希望这会帮助你。

  $ ARR1 =阵列（61,41,41,61,89,90）;
$ ARR2 =阵列（61,41）;$数= array_count_values​​（$ ARR1）;从ARR1 //计数值$结果=阵列（）;
的foreach（$ ARR2为$行）{
    $结果[$行= array_key_exists（$行，$数）？ $计数[$行]：0;
}回声分钟（$结果）;
 

  

$ ARR2 = [61,41]输出：2

  
  

$ ARR2 = [61,41,89]输出：1

I want to count the number of a group array in the array. Example

$arr1 = [61,41,41,61,89,90]
$arr2 = [61,41]
$result = 2    //found 61,41 in $arr1  2 time;

Or Example

$arr1 = [89,61,41,41,61,90]
$arr2 = [61,41,89]
$result = 1    //found 61,41,89 in $arr1  1 time;

How to write the code, or concept?

解决方案

I hope this will help you..

$arr1 = array(61,41,41,61,89,90);
$arr2 = array(61,41);

$count = array_count_values($arr1); //count values from arr1

$result = array();
foreach($arr2 as $row) {
    $result[$row] = array_key_exists($row, $count) ? $count[$row] : 0;
}

echo min($result);

$arr2 = [61,41] output: 2

$arr2 = [61,41,89] output: 1

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