快速/灵活的通知用户信息测试 [英] Quick/Nimble notification userInfo testing
本文介绍了快速/灵活的通知用户信息测试的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我正在查看快速/灵活的通知支持,例如:
I was looking at the notifications support in quick/nimble, e.g.:
expect {
NotificationCenter.default.postNotification(testNotification)
}.to(postNotifications(equal([testNotification]))
有没有办法让我处理返回的通知以检查 userInfo?我的目标是调用一个发布通知的方法,然后检查该通知 userInfo 并确保键/值对正确.
Is there a way to get my hands on the notification that is returned to inspect the userInfo? My goal is to invoke a method that posts a notification, and then inspect that notification userInfo and make sure that the key/value pairs are correct.
快速:2.1.0
敏捷:8.0.1
Quick: 2.1.0
Nimble: 8.0.1
推荐答案
我最终这样做了:
func equalName(_ expectedName: Notification.Name, condition: @escaping (([AnyHashable: Any]) -> Bool)) -> Predicate<[Notification]> {
return Predicate.define("equal <\(stringify(expectedName))>") { actualExpression, msg in
guard let actualValue = try actualExpression.evaluate() else {
return PredicateResult(status: .fail, message: msg)
}
let actualNames = actualValue
.filter { $0.name == expectedName }
.filter { notification in
guard let userInfo = notification.userInfo else {
return false
}
return condition(userInfo)
}
.compactMap { $0.name }
let matches = actualNames.contains(expectedName)
return PredicateResult(bool: matches, message: msg)
}
}
然后在呼叫站点您可以提供条件..
and then at the call site you can provide the condition..
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