在Unix中使用bash查找指定大小的文件 [英] Find files of specified size using bash in Unix
问题描述
我正在寻找一个 Unix 命令来打印文件的大小.我用过这个,但没用.
I am looking for a Unix command to print the files with its size. I used this but it didn't work.
find . -size +10000k -print.
我想打印文件的大小以及文件名/目录.
I want to print the size of the file along with the filename/directory.
推荐答案
find . -size +10000k -exec ls -sd {} +
如果您的 find
版本不接受 +
表示法(其作用与 xargs
类似),那么您可以使用 (GNU find
和 xargs
,所以 find
可能支持 +
反正):
If your version of find
won't accept the +
notation (which acts rather like xargs
does), then you might use (GNU find
and xargs
, so find
probably supports +
anyway):
find . -size +10000k -print0 | xargs -0 ls -sd
或者您可能会用 \;
替换 +
(并忍受相对低效的情况),或者您可能会遇到由名称和使用中的空格引起的问题便携式:
or you might replace the +
with \;
(and live with the relative inefficiency of this), or you might live with problems caused by spaces in names and use the portable:
find . -size +10000k -print | xargs ls -sd
ls
命令上的 -d
确保如果找到目录(不太可能,但是...),则将打印目录信息,而不是目录中的文件.而且,如果您要查找超过 1 MB 的文件(如建议删除的评论),则需要将 +10000k
调整为 1000k
或 +1024k
或 +2048
(对于 512 字节块,-size
的默认单位).这将列出大小,然后列出文件名.当然,您可以通过将 -type f
添加到 find
命令来避免对 -d
的需要.
The -d
on the ls
commands ensures that if a directory is ever found (unlikely, but...), then the directory information will be printed, not the files in the directory. And, if you're looking for files more than 1 MB (as a now-deleted comment suggested), you need to adjust the +10000k
to 1000k
or maybe +1024k
, or +2048
(for 512-byte blocks, the default unit for -size
). This will list the size and then the file name. You could avoid the need for -d
by adding -type f
to the find
command, of course.
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