尝试加入 ps 和 pwdx linux 命令的输出 [英] Trying to join output from ps and pwdx linux commands

问题描述

我正在尝试连接 ps 和 pwdx 命令的输出.谁能指出我命令中的错误.

I am trying to join output from ps and pwdx command. Can anyone point out the mistake in my command.

ps -eo %p,%c,%u,%a --no-headers | awk -F',' '{ for(i=1;i<=NF;i++) {printf $i", 
"} ; printf pwdx $1; printf "\n" }'

我希望每一行的最后一列是进程目录.但它只是显示 $1 的值而不是命令输出 pwdx $1

I expect the last column in each row to be the process directory. But it just shows the value of $1 instead of the command output pwdx $1

这是我的输出样本(1 行):

This is my output sample (1 row):

163957, processA , userA , /bin/processA -args, 163957

我期待

163957, processA , userA , /bin/processA -args, /app/processA

谁能指出我可能遗漏了什么

Can anyone point out what I may be missing

推荐答案

试试这个:

ps -eo %p,%c,%u,%a --no-headers | awk -F',' '{ printf "%s,", $0; "pwdx " $1 | getline; print gensub("^[0-9]*: *","","1",$0);}'

说明:

awk '{print pwdx $1}' 将连接 awk 变量 pwdx(为空)和 $1(pid).因此，实际上，您在输出中只获得了 pid.

awk '{print pwdx $1}' will concatenate the awk variable pwdx (which is empty) and $1 (pid). So, effectively, you were getting only the pid at the output.

为了运行一个命令并得到它的输出，你需要使用这个 awk 结构:

In order to run a command and gets its output, you need to use this awk construct:

awk '{"some command" | getline; do_something_with $0}'
# After getline, the output will be present in $0.

#For multiline output, use this:
awk '{while ("some command" | getline){do_something_with $0}}'
# Each individual line will be present in subsequent run of the while loop.

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