json_en code变为数组对象 [英] json_encode turns array into an object

问题描述

我已经创建了href=\"http://www.jamesthistlewood.co.uk/chatter/index.php\" rel=\"nofollow\">社交媒体网站我正在一个一个但我有一点麻烦json_en code和json_de code。我用数组存储谁已经喜欢上了一个帖子，所以我需要这两种功能，使其可存储，但由于某种原因它有时会保存对象到数据库：

I am have created a 'liking' system for a social media website I'm working on but I'm having a bit of trouble with json_encode and json_decode. I use arrays to store who has liked a post, so I need these 2 functions to make it storable, but for some reason it sometimes saves an object to the database:

{1：管理}

而不是数组（我想）：

[管理员]

这是我的code：

if ($liked_by == NULL){ $liked_by = Array(); }
if (! in_array($user, $liked_by)){
  $liked_by[] = $user;
  $likes = $row['likes']+1;
  $liked_by = json_encode($liked_by);
  mysql_query("UPDATE $stream SET liked_by = '$liked_by' WHERE id = ".$id, $db)
    or die(mysql_error($db));
  mysql_query("UPDATE $stream SET likes = '$likes' WHERE id = ".$id, $db)
    or die(mysql_error($db));
} else{
  if(($liker = array_search($user, $liked_by)) !== false) {
    unset($liked_by[$liker]);
  }
  $likes = $row['likes']-1;
  $liked_by = json_encode($liked_by);
  mysql_query("UPDATE $stream SET liked_by = '$liked_by' WHERE id = ".$id, $db)
    or die(mysql_error($db));
  mysql_query("UPDATE $stream SET likes = '$likes' WHERE id = ".$id, $db)
    or die(mysql_error($db));
}

对不起使用去precated MySQL的功能...

Sorry about using deprecated mysql functions...

我只是不知道发生了什么。
先谢谢了。

I'm just not sure what's happening. Thanks in advance.

推荐答案

您可以为

json_decode($data,true);

其中， $数据是从数据库中保存的数据。

where $data is the saved data from DB.

以上将返回一个数组，你可以操纵它进行进一步的操作。

The above will return an array and you can manipulate it for further operation.

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