PHP：检查从列表中特殊字符字符串中的present [英] PHP: Check if special characters from a list are present in a string

问题描述

这是一个新手的问​​题。

This is a newbie question.

让我们说我有非法字符数组，即：

Let's say I have an array of illegal characters, i.e.:

$special_chars = array("?", "[", "]", "/", "\\", "=", "<", ">", ":", ";", ",", "'", "\"", "&", "$", "#", "*", "(", ")", "|", "~", "`", "!", "{", "}");

我需要检查是否有这些字符是在字符串present，即

I would need to check if any of these characters is present in a string, i.e.

$my_string = "abcde!fgh"

我已经一派一个解决方案以简单的方式来做到这一点，但没有发现任何满意的答案。

I have googled for a solution to do this in a simple manner but haven't found any satisfactory answer.

任何帮助将是非常美联社preciated。

Any help on this would be much appreciated.

推荐答案

一个简洁的方式与你的两个数据结构做将是：

A concise way to do it with your two data structures would be:

count( array_intersect( str_split($my_string), $special_chars ) )

这也将告诉你有多少特殊字符的字符串中

That would also tell you how many of the special characters are in the string.

您本来写一个循环为你的角色列表和 strpos 手动探测。

You could otherwise write a loop for your character list and manually probe with strpos.

最少的努力将是你的特殊字符列表转换为正则表达式charclass将和测试对字符串。

The least effort would be converting your special character list into a regex charclass and testing against the string.

这篇关于PHP：检查从列表中特殊字符字符串中的present的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！