从 URL 中获取前 n 个字节 [英] Fetch first n bytes from the URL

问题描述

是否可以只从某个 URL 获取一些字节，然后关闭与 urllib/urllib2 的连接?或者甚至可能是从第 n 个字节到第 k 个字节的一部分?那边有一个页面，我不需要加载整个页面，只需要加载其中的一部分.

Is that possible to fetch only a number of bytes from some URL and then close the connection with urllib/urllib2? Or even may be a part from n-th byte to k-th? There is a page on that side and I don't need to load the whole page, only a piece of it.

推荐答案

可以设置Range头来请求一定范围的字节，但是您依赖服务器来满足请求:

You can set the Range header to request a certain range of bytes, but you are dependent on the server to honor the request:

import urllib2
req = urllib2.Request('http://www.python.org/')
#
# Here we request that bytes 18000--19000 be downloaded.
# The range is inclusive, and starts at 0.
#
req.headers['Range']='bytes=%s-%s' % (18000, 19000)
f = urllib2.urlopen(req)
# This shows you the actual bytes that have been downloaded.
content_range=f.headers.get('Content-Range')
print(content_range)
# bytes 18000-18030/18031

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