充分利用数组中的元素与德code JSON内容 [英] Getting elements from an array with contents from decode json

问题描述

这有点很难形容在标题的问题，但我会在身体解释。所以我有这个例子JSON（它类似于一个我）：

It's sort of hard to describe the question in the title, but I will explain it in the body. So I have this example JSON (It's similar to the one I have):

[{"AssetId":234234,"Name":"Test1"},{"AssetId":53453,"Name":"Test2"}]

所以基本上我想从主阵列的第一阵列获得由assetid元素。我打电话这PHP，但它不工作

So basically I want to get the AssetId element from the first array of the main array. I am calling this in PHP, but it isn't working

$array = json_decode("[{"AssetId":234234,"Name":"Test1"},{"AssetId":53453,"Name":"Test2"}]");
echo $array[0][0]

所以，我想这将是主要的数组中的第一个数组以得到与Test1的名称的元素由assetid。得到它的帮助？

So I guess that would be the first array in the main array to get AssetId of the element with the Name of Test1. Any help on getting it?

推荐答案

尝试更换单引号的双引号，你的企图将导致意外解析的T_STRING误差

Try replacing the double quotes with single quotes, your attempt will lead to parse error of unexpected T_STRING

取而代之的是

$array = json_decode("[{"AssetId":234234,"Name":"Test1"},{"AssetId":53453,"Name":"Test2"}]");
                     ^        

试试这个：

$array = json_decode('[{"AssetId":234234,"Name":"Test1"},{"AssetId":53453,"Name":"Test2"}]');
foreach($array as $arr){
  echo $arr->AssetId;
}

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