Python tkinter 检查按钮打印 PY_VAR0 [英] Python tkinter check button printing PY_VAR0

问题描述

所以这是从这个问题中大量汲取的代码:

So this is the code, which draws heavily from this question:

如何从 python tkinter 的 for 循环中的列表创建多个复选框.

from tkinter import * 

root = Tk()

enable = {'jack': 0, 'john': 1} 

def actright(x):
    print(enable.get(x))

for machine in enable:
    enable[machine] = Variable()
    l = Checkbutton(root, text=machine, variable=enable[machine], 
                    command=  actright(machine))
    l.pack(anchor = W)

root.mainloop()

我希望输出是:

0
1

相反的输出是:

PY_VAR0
PY_VAR1

如果没有数字前面的PY_VAR"，我如何获得这些值?

How can I get these values without the "PY_VAR" preceding the number?

推荐答案

去掉enable[machine] = Variable()

for machine in enable:
    l = Checkbutton(root, text=machine, variable=enable[machine],
                    command=  actright(machine))
    l.pack(anchor = W)

root.mainloop()

您看到 PY_VAR0 和 PY_VAR1 是因为您使用 enable[machine] = Variable() 将值设置为那些值，这会覆盖这些值在你的字典中，所以你得到你所做的输出是有道理的.

You see PY_VAR0 and PY_VAR1 because you set the values to those with enable[machine] = Variable(), that overwrites the values in your dict so it makes sense that you get the output you do.

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