试图通过字符串数组一个模式用户输入搜索 - 的JavaScript [英] Trying to search through array of strings for a pattern the user inputs - javascript

问题描述

var p = ["array of words", "i really hate the sun", "i'm TIred"]

function findword(contents,pattern){
    var answer;
    var idx;
    var counter = 0;
    var pat_lc = pattern.toLowerCase();
    for (var i = 0; i <= contents.length-1; i++){
        var str_lc = contents[i].toLowerCase();
        idx = str_lc.indexOf(pat_lc)
        if (idx >= 0){
            answer = i
        }
        else{
            answer = "-1"
       }
    }
    alert(answer)
}
findword(p,"words")

我试图找到数组的某个字在字符串数组的索引，但它仅适用于上述阵列中的某些词。例如，在code的最后一行，当我选择要搜索词返回答案和IDX-1的值时，应分别0和9。然而，当我搜索累，答案的值为2，IDX为4（这是正确的）。有些话为什么工作和其他人返回值-1？

I'm trying to find the index of the array for a certain word, in an array of strings, however it only works for certain words in the array above. For example, on the last line of the code, when I chose to search for "words" it returns the value of "answer" and "idx" -1 when it should be 0 and 9 respectively. However, when I search for "tired", the value of "answer" is 2 and "idx" is 4 (which is correct). Why do some words work and others return the value of -1?

推荐答案

您应该尽快停止，你找到一个解决方案。

You should stop as soon as you find a solution.

您的程序，只有当它遍历整个数组停止。但是，如果答案是什么不是在最后一个元素？然后答案将包含 1 。

Your program only stops when it iterated over the whole array. But what if the answer what not in the last element ? Then answer will contain -1.

您可以在 1 的init 答案并继续你的循环只要 I 小于 content.length 和答案等于 1 ： http://jsfiddle.net/#&togetherjs=dbVcN8JkKP

You can init answer at -1 and continue your for loop as long as i is less than content.length and answer is equal to -1 : http://jsfiddle.net/#&togetherjs=dbVcN8JkKP

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