Mysql的抽取PHP数组 [英] Mysql extracting array in Php
问题描述
什么是低于我的MySQL阵列提取的问题:
What is the problem with my mysql array extraction below:
$mysql_array = mysql_query("SELECT * FROM table1 WHERE uid1='$uid1'");
$array = array();
while($row = mysql_fetch_assoc($mysql_array)){
$array[] = $row;
}
$array = array_unique($array);
$array = array_reverse($array);
$emails = array();
$numbers = array();
foreach($array as $row){
$uid2 = $row['uid2'];
$number = number($uid2);
if(strlen($number) > 9){
$numbers[] = array('uid2' => $uid2, 'number' => $number);
}
else{
$email = email($uid2);
$emails[] = array('uid2' => $uid2, 'email' => $email);
}
}
$numbers = array_unique($numbers);
$emails = array_unique($emails);
var_dump($numbers);
var_dump($emails);
一定有什么东西我需要做的资源从MySQL转换为数组。
必须有上述code的一个问题。
这是我得到的的var_dump
取值:阵列(0){}
和阵列(1){[0] =>阵列(2){[UID2] => NULL [电子邮件] => NULL}}
推荐答案
我觉得这是你想要做什么:
I think this is what you're trying to do:
$result = mysql_query("SELECT DISTINCT * FROM table1 WHERE uid1 = '{$uid1}' ORDER BY /* insert column name here, followed by ASC or DESC */");
$table = array();
while ($row = mysql_fetch_assoc($result))
$table[] = $row;
// at this point, each entry in the $table array is one row from 'table1'.
// shouldn't need to do array_unique or array_reverse with the modified SQL query above.
$numbers = $emails = array();
foreach ($table as $row)
{
$number = number($row["uid2"]);
if (strlen($number) > 9 && !in_array($numbers[$row["uid2"]], $number, true))
$numbers[$row["uid2"]][] = $number;
else
{
$email = email($row["uid2"]);
if (!in_array($emails[$row["uid2"]], $email, true))
$emails[$row["uid2"]][] = $email;
}
}
// shouldn't need to do array_unique with the if-statements above
var_dump($numbers);
var_dump($emails);
修改在回答意见问题:
根据您所使用的逻辑,其结果很可能是相同的。上面我举的例子将允许这种情况下为 $号
,而你的榜样将不会:
Based on the logic you are using, the result will probably be the same. My example above will allow this scenario for $numbers
, while your example will not:
array(2)
{
[123] => array(2)
{
[0] => 1234567890, // same as $numbers[456][0]
[1] => 9876543210
},
[456] => array(1)
{
[0] => 1234567890 // same as $numbers[123][0]
}
}
但基于的方式, $号
根据 $ UID2
产生,你可能不会看到任何区别。我的意思是,如果数(123)
收益 1234567890
,那么数(456 )
可能不会返回 1234567890
,所以你可能不会永远碰到这样一个场景,你会看到一个区别。
But based on the way that $number
is generated based on $uid2
, you probably won't see any difference. What I mean is that, if number(123)
returns 1234567890
, then number(456)
probably will not return 1234567890
, so you probably wouldn't ever run into a scenario where you would see a difference.
修改2 在思考这个多一些之后,我敢打赌,你的code可以大大简化这个:
EDIT 2 After thinking about this some more, I'm betting that your code can be greatly simplified to this:
// only selecting uid2 from the table
$result = mysql_query("SELECT DISTINCT uid2 FROM table1 WHERE uid1 = '{$uid1}' ORDER BY /* insert column name here, followed by ASC or DESC */");
$output = array();
while (list($uid2) = mysql_fetch_row($result))
{
$number = number($uid2);
if (strlen($number) > 9)
$output[$uid2]["number"] = $number;
else
$output[$uid2]["email"] = email($uid2);
}
var_dump($output);
过去修改(希望):
// only selecting uid2 from the table
$result = mysql_query("SELECT DISTINCT uid2 FROM table1 WHERE uid1 = '{$uid1}' ORDER BY /* insert column name here, followed by ASC or DESC */");
$numbers = $emails = array();
while (list($uid2) = mysql_fetch_row($result))
{
$number = number($uid2);
if (strlen($number) > 9)
$numbers[$uid2] = $number;
else
$emails[$uid2] = email($uid2);
}
var_dump($numbers);
var_dump($emails);
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