PHP 连接到变量 [英] PHP concatenate to variable

问题描述

我有以下功能可以向选定的用户发送消息

I have the following function that sends a message to selected users

function send_msg($user_id, $title, $message){
$args = array( 'recipients' => $user_id, 'sender_id' => bp_loggedin_user_id(), 'subject' => $title, 'content' => $message );
$thread_id = messages_new_message1( $args );
messages_delete_thread($thread_id,bp_loggedin_user_id());
}

这是由以下发布表单的代码调用

This is invoked by the following code that posts the form

// Get data from form
    $body_input=isset($_POST['body_input'])?$_POST['body_input']:'';
    $subject_input=isset($_POST['subject_input'])?$_POST['subject_input']:'';

// Loop sending a message for each recipient
foreach(array_column($user_ids, 'user_id') as $user_N) {
    send_msg($user_N, $body_input, $subject_input);    
}

我想在send_msg

我试过了

$args = array( 'recipients' => $user_id, 'sender_id' => bp_loggedin_user_id(), 'subject' => $title.'some text', 'content' => $message );

这确实有效，但是当我尝试时

which does work but when I try

$args = array( 'recipients' => $user_id, 'sender_id' => bp_loggedin_user_id(), 'subject' => $title.'some text', 'content' => $message.'some text' );

它发送消息两次，一次带有 title 和 body，另一次带有 title.what_I_append 和 body.what_I_append

It sends the message twice, one with title and body and another with title.what_I_append and body.what_I_append

我也试过这种方式，但没有发布

I have also tried this way but this does not post

$body_input=isset($_POST['body_input'])?$_POST['body_input']:''.'some text to append';

如何正确连接到用于主题和正文的变量?

How can I correctly concatenate to the variables used for subject and body?

推荐答案

按照我的评论快速回答:

A quick answer to follow my comments:

我建议 send_msg() 只关注发送消息.

I would recommend send_msg() focus's only on sending the message.

因此在将这些值发送到 send_msg() 函数之前附加到主题和正文.

Therefore append to the subject and body prior to sending these values to send_msg() function.

<?php

//Personally i wouldnt append to an empty value, your choice.
$subject = isset($_POST['subject_input']) 
    ? $_POST['subject_input'].' appended text'
    : ''
$body= isset($_POST['body_input']) 
    ? $_POST['body_input'].' appended text' 
    : '';

send_msg($user_id, $title, $body);

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