合并基础上,红宝石哈希键和值散列多维数组 [英] Merge multidimensional array of hash based on hash key and value in ruby
本文介绍了合并基础上,红宝石哈希键和值散列多维数组的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有一个数组,我想,以配合在多维数组的散列的其他阵列,
I have one array and i want to match value of id
key with other array of hash in multidimensional array,
input = [
[ {"id"=>"1","name"=>"a"},
{"id"=>"2","name"=>"b"},
{"id"=>"3","name"=>"c"},
{"id"=>"4","name"=>"d"},
{"id"=>"5","name"=>"e"},
{"id"=>"6","name"=>"f"}
],
[ {"id"=>"3","hoby"=>"AA"},
{"id"=>"3","hoby"=>"BB"},
{"id"=>"1","hoby"=>"CC"},
{"id"=>"1","hoby"=>"DD"},
{"id"=>"4","hoby"=>"EE"}
],
[ {"id"=>"1","language"=>"A"},
{"id"=>"1","language"=>"B"},
{"id"=>"2","language"=>"B"},
{"id"=>"2","language"=>"C"},
{"id"=>"6","language"=>"D"}
]
]
我需要阵列输出一样,
I need array output like,
output = [
{"id"=>"1","name"=>"a","id"=>"1","hoby"=>"CC","id"=>"1","language"=>"A","id"=>"1","language"=>"B"},
{"id"=>"2","name"=>"b","id"=>"2","language"=>"B"},
{"id"=>"3","name"=>"c","id"=>"3","hoby"=>"AA","id"=>"3","hoby"=>"BB"},
{"id"=>"4","name"=>"d","id"=>"4","hoby"=>"EE"},
{"id"=>"5","name"=>"e"},
{"id"=>"6","name"=>"f","id"=>"6","language"=>"D"}
]
我已经写了code本,
I have wrote code for this,
len = input.length - 1
output = []
input[0].each do |value,index|
for i in 1..len
input[i].each do |j|
if value["id"] == j["id"]
output << value.merge(j)
end
end
end
end
但我正在逐渐错误输出array.There可能是任何数量的多维数组子数组。
But i am getting wrong output array.There might be any number of sub array in multidimensional array.
感谢,
推荐答案
这也许可以帮助你。
input = [
[
{"id"=>"1","name"=>"a"},
{"id"=>"2","name"=>"b"},
{"id"=>"3","name"=>"c"},
{"id"=>"4","name"=>"d"},
{"id"=>"5","name"=>"e"},
{"id"=>"6","name"=>"f"}
],
[
{"id"=>"3","hoby"=>"AA"},
{"id"=>"3","hoby"=>"BB"},
{"id"=>"1","hoby"=>"CC"},
{"id"=>"1","hoby"=>"DD"},
{"id"=>"4","hoby"=>"EE"}
],
[
{"id"=>"1","language"=>"A"},
{"id"=>"1","language"=>"B"},
{"id"=>"2","language"=>"B"},
{"id"=>"2","language"=>"C"},
{"id"=>"6","language"=>"D"}
]
]
这种方式可以让你的之类的结果。
This way you can make your "sort" results.
output = {}
input.flatten.each do |h|
output[h["id"]] = {} unless output[h["id"]]
output[h["id"]].merge!(h)
end
output.values
# => [
# => {"id"=>"1", "name"=>"a", "hoby"=>"DD", "language"=>"B"},
# => {"id"=>"2", "name"=>"b", "language"=>"C"},
# => {"id"=>"3", "name"=>"c", "hoby"=>"BB"},
# => {"id"=>"4", "name"=>"d", "hoby"=>"EE"},
# => {"id"=>"5", "name"=>"e"},
# => {"id"=>"6", "name"=>"f", "language"=>"D"}
# => ]
但更好的方法是在输入使用哈希。您可以定义像哈希输入ID之类的关键,所以如果你生成数据,你没有问题排序。
成才这样
{
"1" => {"name" => "a", "hoby" => "DD", "language" => "B"}
}
这篇关于合并基础上,红宝石哈希键和值散列多维数组的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!
查看全文