XPath:选择所有A节点和所有不在A节点内的B节点 [英] XPath: select all A nodes and all B nodes that are not inside an A node

查看:41
本文介绍了XPath:选择所有A节点和所有不在A节点内的B节点的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

在一个 XPath 表达式中是否可能出现以下情况(参见下面的示例):

Is the following possible in one XPath expression (see sample below):

选择所有(msg 类的span 标签) AND 所有((具有非空alt 属性的img 标签) AND (不在内部msg 类的 span 标签))

Select all (span tags of class msg) AND all ((img tags that have a non-empty alt attribute) AND (are NOT located inside a span tag of class msg))

简化示例:

<span class="msg">Message text A</span>
<img alt="" />
<span class="msg">Message text B <img alt="text A" /></span>
<span class="err">Error text C <img alt="text B" /></span>
<img alt="text C" />
<span class="err">Error text D</span>

结果节点集应包含:

<span class="msg">Message text A</span>
<span class="msg">Message text B <img alt="text A" /></span>
<img alt="text B" />    
<img alt="text C" />

推荐答案

未测试,但类似?

//span[@class='msg'] | //img[@alt!='' and not(ancestor::span[@class='msg'])]

这篇关于XPath:选择所有A节点和所有不在A节点内的B节点的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆