从布局中按名称获取小部件 [英] get widgets by name from layout

问题描述

如果我想从 python Qt 的布局中获取特定的小部件，我应该如何进行?

How should I proceed if I want to get an especific widget from a layout in python Qt?

到目前为止我做了什么:

What I have done so far:

for i in range(self.ui.horizontalLayout_14.count()): 
    #here it does fail
    name = self.ui.horizontalLayout_14.itemAt(i).objectName()

    #if the above would had worked, then I could do something like this for example
    if "button" in name:
        self.ui.horizontalLayout_14.itemAt(i).widget().close()

请注意，例如，我使用的是 button，但它可能是布局、lineEdit 或组合框、标签等中的任何小部件，但并非全部.>

Note that, for the example, I am using button but It might be whatever widget inside the layout, lineEdit, or comboBox, labels, etc etc, but not all of them though.

推荐答案

问题在于 itemAt() 函数返回 QLayoutItem 而不是小部件.所以你必须调用 QLayoutItem::widget() 函数来获取包含的小部件，即:

The problem is that itemAt() function returns the QLayoutItem and not a widget. So you have to call the QLayoutItem::widget() function to get the containing widget, i.e.:

name = self.ui.horizontalLayout_14.itemAt(i).widget().objectName()

更新

但是，使用 QObject::findChild() 函数可以更轻松地完成同样的工作.即:

However, you can do the same much easier with using the QObject::findChild() function. I.e.:

widget = self.ui.findChild(QPushButton, "button")
# Check whether the returned widget is null...

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