不兼容的 var 类型 [英] Incompatible var types
问题描述
以下错误是@GetFullPathName() 函数
The below errors are @ the GetFullPathName() function
1 IntelliSense: argument of type "const char *" is incompatible with parameter of type "LPCWSTR"
2 IntelliSense: argument of type "char *" is incompatible with parameter of type "LPWSTR"
当我尝试运行我的程序时,我不断收到上述错误.变量是适当的类型,但它一直在说别的?关于为什么会这样的任何想法?我认为没有必要对它们进行类型转换.
I keep getting the above errors when I try to run my program. The variables are of the appropriate type, yet it keeps saying otherwise? Any ideas as to why this is? I don't think it's necessary to type cast them.
#include "stdafx.h"
using namespace std;
int main(int argc, _TCHAR* argv[])
{
/* Get path of DLL we're loading */
string name;
cin >> name;
const char* DLL_NAME = name.c_str();
HWND handle = FindWindow(0, L"Calculator");
if(handle == NULL){
cout << "Couldn't find process window!" << endl;
}else{
cout << "Process window found, continuing..." << endl;
DWORD id;
GetWindowThreadProcessId(handle, &id);
char DLL_LOCATION[MAX_PATH] = {0};
GetFullPathName(DLL_NAME, MAX_PATH, DLL_LOCATION, NULL);
}
return 0;
}
推荐答案
变量是合适的类型,但它一直说不是?
The variables are of the appropriate type, yet it keeps saying otherwise?
不,他们不是.LPCWSTR
和 LPWSTR
分别是 const wchar_t*
和 wchar_t*
的别名.为此,您必须使用 std::wstring
而不是 std::string
.
No they aren't. LPCWSTR
and LPWSTR
are aliases for const wchar_t*
and wchar_t*
respectively. You'll have to use std::wstring
instead of std::string
for this.
其含义的细分:
LPCWSTR
:指向常量宽字符串的长指针LPWSTR
:指向宽字符串的长指针
LPCWSTR
: Long Pointer to Const Wide StringLPWSTR
: Long Pointer to Wide String
或者,您可以不将项目编译为 unicode(通过将字符集更改为多字节 IIRC),这样 Windows API 将需要常规"字符串.
Alternatively you could not compile your project as unicode (by changing the character set to Multi-Byte IIRC), that way the Windows API will expect "regular" strings.
我应该注意到,就像字符串有一个广泛的类似物一样,std::cout
和 std::cin
也有 std 的形式::wcout
和 std::wcin
.
I should note that just like strings have a wide analogue so do std::cout
and std::cin
in the form of std::wcout
and std::wcin
.
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