以编程方式加载文件 [英] Programmatically load files
问题描述
当我想将文件加载到 R 中时,有什么方法可以通过编程(或半编程)而不是手动复制粘贴路径并将 \
切换到 /
所以 R 可以读取它(因为 \
是 R 中的转义字符)
When I want to load a file into R, what would be a way to do so programmatically (or semi programmatically) instead of just manually copy paste the path and switch \
to /
so R could read it (because \
is an escape character in R)
@Roland 提到的一种方法是使用 scan
One method mentioned by @Roland is using scan
list.files(scan(file=file(description = "clipboard"), what = "character", allowEscapes = FALSE))
如果路径包含空格,则需要修改
Which will need modifications if the path contains a space like
C:\用户\大卫阿伦堡\"
"C:\Users\David Arenburg\"
推荐答案
normalizepath
也许你在找什么:
> normalizePath(c(R.home(), tempdir()))
[1] "C:\\Program Files\\R\\R-3.1.0"
[2] "C:\\Users\\john\\AppData\\Local\\Temp\\RtmpysKuFi"
> normalizePath(c(R.home(), tempdir()), winslash = '/')
[1] "C:/Program Files/R/R-3.1.0"
[2] "C:/Users/john/AppData/Local/Temp/RtmpysKuFi"
如果您使用的是 Windows 并且在复制和粘贴文件路径时遇到问题,请使用 readClipboard
.例如,我从 Windows 文件夹中复制了一个文件路径,因此它位于剪贴板上,然后我可以使用:
Use readClipboard
if you are on windows and have problems copying and pasting filepaths. For example I copy a file path from a windows folder so it is on the clip board then I can use:
> readClipboard()
[1] "C:\\Users\\john\\AppData\\Local\\Temp"
然后您可以使用 `normalizePath 来纠正路径的 Windows 风格.
You can then use `normalizePath to correct the windows flavour of paths.
这篇关于以编程方式加载文件的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!