如何使用 Java 在 Windows 中获取短文件名? [英] How to get short-filenames in Windows using Java?

问题描述

我需要使用 Java(tm) 确定存储在 Windows 系统上的文件的短文件名.

I need to determine the short-filenames of files, stored on a Windows system, using Java(tm).

推荐答案

Self Answer

有相关问题，有相关答案.然而，我发布了这个解决方案，因为它使用 Java(tm) 代码而不需要外部库.欢迎针对不同版本的 Java 和/或 Microsoft(R) Windows(tm) 提供其他解决方案.

Self Answer

There are related questions with related answers. I post this solution, however, because it uses Java(tm) code without the need for external libraries. Additional solutions for different versions of Java and/or Microsoft(R) Windows(tm) are welcome.

主要概念在于通过运行时类从Java(tm)调用CMD:

Main concept lies in calling CMD from Java(tm) by means of the runtime class:

cmd/c for %I in ("[长文件名]") do @echo %~fsI

cmd /c for %I in ("[long file name]") do @echo %~fsI

解决方案

在运行在 Windows 7 系统上的 Java SE 7 上测试(为简洁起见，代码已减少).

Solution

Tested on Java SE 7 running on Windows 7 system (Code has been reduced for brevity).

    public static String getMSDOSName(String fileName)
    throws IOException, InterruptedException {

    String path = getAbsolutePath(fileName);

    // changed "+ fileName.toUpperCase() +" to "path"
    Process process =
        Runtime.getRuntime().exec(
            "cmd /c for %I in (\"" + path + "\") do @echo %~fsI");

    process.waitFor();

    byte[] data = new byte[65536];
    int size = process.getInputStream().read(data);

    if (size <= 0)
        return null;

    return new String(data, 0, size).replaceAll("\\r\\n", "");
}

public static String getAbsolutePath(String fileName)
    throws IOException {
    File file = new File(fileName);
    String path = file.getAbsolutePath();

    if (file.exists() == false)
        file = new File(path);

    path = file.getCanonicalPath();

    if (file.isDirectory() && (path.endsWith(File.separator) == false))
        path += File.separator;

    return path;
}

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