计算 Mathematica 中每组的磁头数 [英] Count the number of heads per set in Mathematica
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问题描述
首先感谢大家的回复.我正在尽我最大的努力跟上所有的建议.但是我正在努力保持正轨.
First of all, thank you for all your responces. I am doing my best to keep up with all the suggestions. However I'm trying to stay on track.
所以现在我有
s = Table[RandomChoice[{Heads, Tails}, 2 i + 1], {i, 10}];
接下来,我想计算每个i"出现的Heads"的数量.
Next, I want to count the number of "Heads" that occur for each "i".
我可以为一个案例做到这一点....说 5,
I can do this for one case....say 5,
n = RandomChoice[{Heads, Tails}, 5];
n1 = Count[n, Heads];
但是我无法扩展它....
But I am having trouble expanding this....
再次感谢.
附言什么是投反对票?太简单了?
p.s. what are down votes? Too easy?
推荐答案
Map (/@
) 统计列表中人头数的功能:
Map (/@
) the function of counting heads in a list:
Count[#, Heads]&
到s
中的每个子列表.因此:
to each sublist in s
. Hence:
Count[#, Heads]& /@ s
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