从 WSGI 脚本获取 URL [英] getting URL from WSGI script

问题描述

所以我想根据用户的 URL(或至少是用户的域)从 WSGI 文件调用 Python 代码的不同实例.我们在 Apache 2.x + Python + Django 堆栈上运行.

So I want to invoke different instances of Python code based on user's URL (or at least user's domain) from WSGI file. We're running on Apache 2.x + Python + Django stack.

在 WSGI 脚本(这里和此处).然而，这个键丢失了，下面是 os.environ.__dict__ 在一切正常时的样子:

Looks like there should be something like 'SERVER_NAME' or 'HTTP_HOST' key in the os.environ dictionary accessible in WSGI script (here and here). However this key is missing and here's how os.environ.__dict__ looks like when everything is working properly:

{'data': {'LANG': 'C', 'APACHE_LOCK_DIR': 'xxx', 'TZ': 'US/Pacific', 'DJANGO_SETTINGS_MODULE': 'xxx', 'APACHE_RUN_USER': 'xxx', 'PWD': 'xxx', 'APACHE_PID_FILE': 'xxx', 'CELERY_LOADER': 'django', 'APACHE_RUN_DIR': 'xxx', 'APACHE_LOG_DIR': 'xxx', 'APACHE_RUN_GROUP': 'xxx', 'HOME': 'xxx', 'PATH': 'xxx'}}

域/URL 是一个非常基本的信息，我很惊讶我找不到它.

Domain/URL is a very basic info and I'm surprised I'm failing to find it.

更新:我已经决定采用不同的方法(使用 Apache Config 而不是 WSGI 脚本).这似乎解决了缺少 WSGI 环境变量的问题.感谢您的所有回复！

UPDATE: I've settled on a different approach (using Apache Config instead WSGI script). That seems to solve the issue of missing WSGI environment variable. Thanks for all your responses!

推荐答案

你混淆了显示当前系统环境变量的 os.environ dict 和 environ作为参数传递给 wsgi 应用程序.路径在后者.

You're confusing the os.environ dict that shows the current system environment variables with the environ that is passed to the wsgi application as a parameter. The path is in the latter.

但是，由于您使用的是 Django，所有这些信息都可以通过 request 对象获得.

However, since you're using Django, that information is all made available via the request object.

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