XCode C++ 缺少精子() [英] XCode C++ missing sperm()

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本文介绍了XCode C++ 缺少精子()的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我正在使用 C++ 和 XCode 创建一个 cmd 行应用程序来保存文件权限,但是我无法识别精子 () 方法,错误是

I'm using C++ and XCode to create a cmd line app to save file permissions, however I can't get the sperm() method to be identified, the error is

'使用未声明的标识符'精子'

'Use of undeclared identifier 'sperm'

我的包含和有问题的代码如下......

My includes and the piece of code in question are below ...

// My includes ...
#include <iostream>
#include <stdio.h>
#include <sys/types.h>
#include <dirent.h>
#include <string.h>
#include <vector>
#include <sys/stat.h>
#include <dirent.h>
#include <pwd.h>
#include <grp.h>
#include <time.h>
#include <locale.h>
#include <langinfo.h>
#include <stdint.h>

// Code fragment ...

dp = opendir ("/var/someplace");
if (dp != NULL)
{
    while ((ep = readdir (dp)))
    {

        oFile = new FileObject;

        oFile->setName( ep->d_name );
        oFile->setIsDirectory( ep->d_type == isFolder );

        oFiles.push_back (*oFile);            
        // If it's a folder then we can get it's innards 

        if (stat(ep->d_name, &statbuf) == -1)
            continue;
        cout << "%10.10s", sperm(statbuf.st_mode);

        iFile++;
    }



    closedir (dp);
}
else
    perror ("Couldn't open the directory");

推荐答案

这可能让我看起来像个变态,但我在谷歌上搜索了精子"(当然只搜索 .h 和 .cpp 文件).坏消息是我找不到任何对它的引用(除了 stat 函数 页面本身).

This might make me look like a pervert, but I searched google for 'sperm' (ofcourse only for .h and .cpp files). The bad news is I can't find any references to it (except on the stat function page itself).

好消息是我发现了 这段 代码定义了它自己的精子"功能:

The good news is I found this piece of code which defines it's own 'sperm' function:

char const * sperm(__mode_t mode) {
    static char local_buff[16] = {0};
    int i = 0;
    // user permissions
    if ((mode & S_IRUSR) == S_IRUSR) local_buff[i] = 'r';
    else local_buff[i] = '-';
    i++;
    if ((mode & S_IWUSR) == S_IWUSR) local_buff[i] = 'w';
    else local_buff[i] = '-';
    i++;
    if ((mode & S_IXUSR) == S_IXUSR) local_buff[i] = 'x';
    else local_buff[i] = '-';
    i++;
    // group permissions
    if ((mode & S_IRGRP) == S_IRGRP) local_buff[i] = 'r';
    else local_buff[i] = '-';
    i++;
    if ((mode & S_IWGRP) == S_IWGRP) local_buff[i] = 'w';
    else local_buff[i] = '-';
    i++;
    if ((mode & S_IXGRP) == S_IXGRP) local_buff[i] = 'x';
    else local_buff[i] = '-';
    i++;
    // other permissions
    if ((mode & S_IROTH) == S_IROTH) local_buff[i] = 'r';
    else local_buff[i] = '-';
    i++;
    if ((mode & S_IWOTH) == S_IWOTH) local_buff[i] = 'w';
    else local_buff[i] = '-';
    i++;
    if ((mode & S_IXOTH) == S_IXOTH) local_buff[i] = 'x';
    else local_buff[i] = '-';
    return local_buff;
}

用法很简单:

#include <sys/types.h>
#include <sys/stat.h>
#include <iostream>

int main(int argc, char ** argv)
{
    std::cout<<sperm(S_IRUSR | S_IXUSR | S_IWGRP | S_IROTH)<<std::endl;
    std::cout<<sperm(S_IRUSR)<<std::endl;
    std::cout<<sperm(S_IRUSR | S_IRGRP | S_IWOTH | S_IROTH)<<std::endl;
    return 0;
}

ideone 上的输出:

r-x-w-r--
r--------
r--r--rw-

这篇关于XCode C++ 缺少精子()的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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