通过为 Swift 中的每个字符提供两种可能性来比较字符串 [英] Compare a string by giving two possibilities for each character in Swift

问题描述

我需要通过在 (if) 语句中为字符串中的每个字符提供两种可能性来比较字符串，例如:

I need to compare a string by giving two possibilities for each character in the string in an (if) statement eg:

let str = "2 3 1 2"
if str == "(1||2) (2||3) (1||2) (1||2)" {
//Do Something
}

我知道代码写得不正确，但只是为了理解我的意思.

I know the code is not written correctly, but just to understand what I mean.

我曾经在 VB 中使用 (Like Operator) 例如:

I used to use (Like Operator) in VB eg:

Dim s As String = "2 3 1 2"
If s Like "[1-2] [3-4] [2-3] [1-2]" Or s Like "[1-2] [1-2] [2-3] 2"  Then
//Do something
End If

我在 swift 中找不到类似的东西.

I couldn't find anything similar in swift.

请帮忙，谢谢.

推荐答案

您描述的问题迫切需要使用 正则表达式.

The problem you describe is crying out to solved using regular expressions.

上次我查看时，Swift 不支持正则表达式，但它允许使用 NSRegularExpression.请参阅Swift 中的正则表达式 以正则表达式类为例.

Last time I looked, Swift did not support regular expressions, but it does allow use of NSRegularExpression. See Regex in Swift for an example of a Regex class.

所以你最终会写出类似的东西

So you'd end up writing something like

if Regex("[12] [23] [12] [12]").test("2 3 1 2") {
  println("matches pattern")
}

关于此主题的另一篇博文是清洁正则表达式在 Swift 中.

Another blog post on this topic is Clean Regular Expressions In Swift.

这篇关于通过为 Swift 中的每个字符提供两种可能性来比较字符串的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！