xcode 表视图控制器搜索多个数组 [英] xcode table view controller search multiple arrays

问题描述

我添加了一个可以成功搜索菜单名称的搜索栏.但是，菜单价格根本没有过滤，我不知道如何控制这两个数组，当我搜索并获得 menu["a" , "c"] 的结果时，价格数组显示与菜单数组对应的价格；价格[a 的价格"，c 的价格"].该列表显示三个对象；菜单图片、菜单名称和价格.

I've added a search bar that successfully searches through the menu names. However, the menu price does not filter at all, and I don't know how to control the two arrays in a way that when I search and get a result of menu["a" , "c"], the price array displays the prices that are correspondant to the menu array; price["Price of a", "Price of c"]. The list displays three objects; image of the menu, name of the menu, and the price.

var menu = ["Ice Tea (Large)", "Ice Tea (Small)", "Green Apple Refresher (Large)","Green Apple Refresher (Small)", "Peach Refresher (Large)", "Peach Refresher (Small)"]
var price = ["Rs.80", "Rs.50", "Rs.110", "Rs.80", "Rs.110", "Rs.80"]
var currentMenuNameArray = [String]()
class myMenu: UITableViewController, UISearchBarDelegate
{

@IBOutlet weak var tdMenuSearchBar: UISearchBar!

override func viewDidLoad()
{
    super.viewDidLoad()
    tdMenuSearchBar.delegate = self
    currentMenuNameArray = menu
}
override func tableView(_ tableView: UITableView, numberOfRowsInSection section: Int) -> Int {
    return currentMenuNameArray.count
}
override func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {
    let cell = tableView.dequeueReusableCell(withIdentifier: "cell", for: indexPath) as!TigersDenTableViewCell

    cell.tdMenuImage.image = UIImage(named:currentMenuNameArray[indexPath.row] + ".jpg")
    cell.tdMenuName.text = currentMenuNameArray[indexPath.row]
    cell.tdMenuPrice.text = price[indexPath.row]

    return cell
}
override func tableView(_ tableView: UITableView, heightForRowAt indexPath: IndexPath) -> CGFloat
{
    return 100
}
func searchBar(_ searchBar: UISearchBar, textDidChange searchText: String)
{
    guard !searchText.isEmpty else {
        currentMenuNameArray = menu
        tableView.reloadData()
        return
    }
    currentMenuNameArray = menu.filter( { (menu:String) -> Bool in        menu.lowercased().contains(searchText.lowercased())
    })
    tableView.reloadData()
}
}

推荐答案

var menu = ["Ice Tea (Large)", "Ice Tea (Small)", "Green Apple Refresher (Large)","Green Apple Refresher (Small)", "Peach Refresher (Large)", "Peach Refresher (Small)"]
var price = ["Rs.80", "Rs.50", "Rs.110", "Rs.80", "Rs.110", "Rs.80"]

问题是 menu 和 price 是同步的.这意味着如果您从 menu 中删除一项，则需要在 price 中删除相应的一项(相同的索引).但是让它们手动同步会增加工作要做，而对它们使用单​​个数组就足够了，而且更有意义.

The issue is that menu and price are sync'ed. Meaning that if you remove one item from menu, you need to remove the corresponding one (same index) in price. But keeping them manually sync'ed is adding work to do, while using a single array for them is enough and makes more sense.

快速解决方案:使用字典数组:

Quick solution: Use an array of Dictionaries:

var menu:[[String:String]] = ["Name":"Ice Tea (Large)", "Price":"Rs.80",
                              "Name":"Ice Tea (Small)", "Price":"Rs.50",
                              ...]

那么:

cell.tdMenuImage.image = UIImage(named:currentArray[indexPath.row]["Name"] + ".jpg")
cell.tdMenuName.text = currentArray[indexPath.row]["Name"]
cell.tdMenuPrice.text = currentArray[indexPath.row]["Price"]

还有:

currentMenuNameArray = menu.filter( { (menu:[String:String]) -> Bool in   
    menu["Name"].lowercased().contains(searchText.lowercased())
})

我不知道你的代码的范围，但我建议创建你自己的对象/结构，带有一个字符串属性name，一个双属性price，可能是自定义枚举中的一个属性来定义它是大还是小.

I don't know the scope of your code, but I'd suggest to create your own object/struct, with a String Property name, a Double property price, maybe a property from a custom enum to define if it's large or small.

这不是漂亮的 Swift 代码，但更多的是解释逻辑，以及使用自定义对象能给您带来什么好处:

It's not beautiful Swift code, but it's more to explain the logic, and what could give you the benefits of using custom objects:

import UIKit

enum MenuSize: String {
    case small = "Small"
    case large = "Large"
}

class Menu: NSObject {
    let name: String
    let price: Double
    let size: MenuSize

    required init(withName name: String, withPrice price: Double, andSize size: MenuSize) {
        self.name = name
        self.price = price
        self.size = size
    }

    func displayableName() -> String {
        return name + " (" + self.size.rawValue + ")"
    }

    func imageName() -> String {
        return self.name + ".jpg"
    }
}

要测试的示例代码:

let menu1 = Menu.init(withName: "Ice tea", withPrice: 0.80, andSize: .large)
let menu1Name = menu1.displayableName()
print("menu1Name: \(menu1Name)")

let menu2 = Menu.init(withName: "Ice tea", withPrice: 0.50, andSize: .small)
let menu3 = Menu.init(withName: "Diet Coke", withPrice: 0.50, andSize: .small)
let menu4 = Menu.init(withName: "Diet Coke", withPrice: 1.00, andSize: .large)

let array = [menu1, menu2, menu3, menu4]

let filtered = array.filter { (menuToTest:Menu) -> Bool in
    return menuToTest.name.lowercased().contains("et".lowercased())
}

您可以使用 NumberFormatter 以卢比显示价格.(相关 SO 问题).

You could use a NumberFormatter to display the price with Rupees. (Related SO question).

tableView(_ tableView:cellForRowAt:)中的代码就是:

let currentMenu = currentArray[indexPath.row]
cell.tdMenuImage.image = UIImage(named: currentMenu.imageName())
cell.tdMenuName.text = currentMenu.displayableName()
cell.tdMenuPrice.text = //Use the formatter

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