属性不相等或不存在的元素的 XPath [英] XPath for elements with attribute not equal or does not exist

问题描述

我有以下 XML 格式:

I have the following XML format:

<test>
 <table>
   <rows>
     <row ID = "1" Name ="A"/>
     <row ID = "2" SubID = "1" Name ="B"/>
     <row ID = "3" Name ="C"/>
     <row ID = "4" SubID = "1" Name ="D"/>
     <row ID = "5" Name ="E"/>
     <row ID = "4" SubID = "2" Name ="E"/>
   </rows>
   .
   .
 </table>
</test>

我想获取所有行，除了那些具有 SubID = 1 的行.

I would like to take all the rows except the ones that do have SubID = 1.

难点在于，并非所有行都具有名为 SubID 的属性，并且并非所有具有 SubID 属性的行都具有相同的属性价值.

The hard part of this, is that not all the rows have attribute called SubID, and that not all the rows with the attribute SubID, have same value.

理想的输出应该是:

<row ID = "1" Name ="A"/>
<row ID = "3" Name ="C"/>
<row ID = "5" Name ="E"/>
<row ID = "4" SubID = "2" Name ="E"/>

我尝试使用否定值的 XPath，但这不起作用:

I have tried to use an XPath with negation on value, but this won't work:

/test/table/row/not(@SubID=1)

有什么帮助吗?

推荐答案

困难的部分"其实很简单: 一个基本的

element[not(@attribute='value')]

谓词将排除元素没有属性和元素，其中attribute 等于 value.

predicate will exclude elements without the attribute and elements for which attribute equals value.

因此，在您的特定情况下，所有 @SubID 不等于 1 的 row 元素:

So, in your specific case, all row elements that do not have @SubID equal to 1:

/test/table/rows/row[not(@SubID = '1')]

选择

<row ID="1" Name="A"/>
<row ID="3" Name="C"/>
<row ID="5" Name="E"/>
<row ID="4" Name="E" SubID="2"/>

根据要求.

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