需要删除 <?xml version="1.0";编码=“utf-16"?>从 xml [英] Need to remove <?xml version="1.0" encoding="utf-16"?> from the xml

问题描述

我正在通过将 xsl 应用到 xml 输入来生成 xml.我需要没有这部分的输出 "<?xml version="1.0" encoding="utf-16"?>"

Hi i am generating a xml by appying the xsl to a xml input. I need the output without this part "<?xml version="1.0" encoding="utf-16"?>"

输入--xml

<?xml version="1.0" encoding="utf-8"?>
<soap:Envelope xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/"     xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<soap:Body>
<CreateResponse xmlns="http://jerseytelecom.com/">
    <CreateResult>
        <ISD_XMLGateway>
            <Entity>RIM_BPS</Entity>
         </ISD_XMLGateway>
    </CreateResult>
   </CreateResponse>
</soap:Body>
</soap:Envelope> 

我的 xsl

    <?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:JT="http://jerseytelecom.com/" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" exclude-result-prefixes="JT">
         <xsl:output method="xml" indent="yes"/>
         <xsl:template match="/">
           <xsl:element name="Entity">
            <xsl:value-of select="soap:Envelope/soap:Body/JT:CreateResponse/JT:CreateResult/JT:ISD_XMLGateway/JT:Entity"/>  
            </xsl:element>
            </xsl:template>
            </xsl:stylesheet>

电流输出

   <?xml version="1.0" encoding="utf-16"?>
    <Entity>RIM_BPS</Entity>

预期输出

    <Entity>RIM_BPS</Entity>

推荐答案

尝试将 omit-xml-declaration="yes" 属性添加到您的 xsl:output 标记.

Try adding the omit-xml-declaration="yes" attribute to your xsl:output tag.

它应该是这样的:

<xsl:output method="xml" indent="yes" omit-xml-declaration="yes" />

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