可以用antixml来创建xml文档吗? [英] Can you use antixml to create xml documents?

问题描述

有一些使用 Anti-Xml 从 XML 文档中提取信息的示例，但我找不到使用 Anti-Xml 创建 XML 文档的示例.Anti-Xml 是否支持创建文档，或者我应该为此使用另一个库(哪个?).有没有人有用 Anti-Xml 创建 XML 文档的例子?

there are a few examples for using Anti-Xml to extract information from XML documents, but none that I could find of using Anti-Xml to create XML documents. Does Anti-Xml support creating documents, or should I use another library for this (which one?). Does anyone have an example of creating an XML document with Anti-Xml?

推荐答案

是的，您可以构建(和序列化)XML 文档:

Yes, you can build (and serialize) XML documents:

import com.codecommit.antixml._

val doc = Elem(None, "doc", Attributes(), Map(), Group(
  Elem(None, "foo", Attributes("id" -> "bar"), Map(), Group(Text("baz")))
))

val writer = new java.io.StringWriter
val serializer = new XMLSerializer("UTF-8", true)

serializer.serializeDocument(doc, writer)

您还可以使用 Anti-XML 的 zippers 来做一些有趣的编辑技巧:>

You can also use Anti-XML's zippers to do some interesting editing tricks:

val foos = doc \ "foo"
val newFoo = foo.head.copy(children = Group(Text("new text!")))
val newDoc = foos.updated(0, newFoo).unselect

现在 newDoc 包含编辑过的文档:

Now newDoc contains the edited document:

scala> newDoc.toString
res1: String = <doc><foo id="bar">new text!</foo></doc>

Zipper doc \ "foo" 返回的不同于 NodeSeq 因为它携带有关其上下文的信息，这允许您撤消"由\ 完成的选择操作.

The Zipper that doc \ "foo" returns is different from a NodeSeq in that it carries information about its context, which allows you to "undo" the selection operation done by \.

更新以响应 ziggystar 在下面的评论:如果你想要像 Scala 的 XML 文字这样的东西，你可以使用convert 在任何 scala.xml.Elem 上:

Update in response to ziggystar's comment below: if you want something like Scala's XML literals, you can just use convert on any scala.xml.Elem:

val test: com.codecommit.antixml.Elem = <test></test>.convert

我认为问题与程序化创建有关.

I'd assumed the question was about programmatic creation.

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