使用 C# 生成 XML [英] XML generation using c#
本文介绍了使用 C# 生成 XML的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
我的目标是生成这种格式的xml结构
My goal is to generate xml structure in this format
<?xml version='1.0' encoding='UTF-8'?>
<return xmlns:rmas="value here" xmlns:xsi="value here" xsi:noNamespaceSchemaLocation="value here">
<header>
<return-code>""</return-code>
<return-desc>""</return-desc>
<as-at-date>""</as-at-date>
<operator-code>""</operator-code>
</header>
<body>
<scheme>
<code>10050</code>
<employer>
<empr-code></empr-code>
<data>
<serial-no />
<pin />
<employer-contribution />
<employee-contribution />
<voluntary-contribution />
<total-contribution />
</data>
</employer>
</scheme>
<scheme>
<code>10100</code>
<employer>
<empr-code></empr-code>
<data>
<serial-no />
<pin />
<employer-contribution />
<employee-contribution />
<voluntary-contribution />
<total-contribution />
</data>
</employer>
</scheme>
[...]
</body>
</return>
这是我消费的数据样本
scheme-code emp-code pin empr-contr empyee-contr total total-vol-cont
10050 PR0000395010 PEN200386572133 54777.28 43821.82 108599.1 10000
10050 PR0000679771 PEN200629902715 65528.34 0 215528.34 150000
10050 PR0000007340 PEN200629902715 0 65528.34 215528.34 150000
10050 PU000035E001 PEN100786299723 10570.34 10570.34 21140.68 0
10050 TCF000615630 PEN100786299723 12060.15 12060.16 24120.31 0
10050 TCF000615630 PEN100786299723 12204.98 12204.99 24409.97 0
10050 PR0000615630 PEN100144364216 10945.19 13681.49 24626.68 0
10050 PR0000615630 PEN100453089112 14319.32 17899.15 32218.47 0
10050 PR0000615630 PEN200742682512 13116.33 16395.41 29511.74 0
10100 PRTEMP005022 PEN100940140007 792 990 1782 0
10100 PRTEMP005022 PEN100799131715 2375 2970 5345 0
10100 PRTEMP005022 PEN100799212715 831.6 1039.5 1871.1 0
在 body 标签中，我想首先按方案代码和代码内部对数据进行分组，然后按该方案中的 emp 代码对数据进行分组，然后按数据(pin、empr-contr、empyee-contr...) 拥有 empr-code.每个数据标签的 serial-no(int) 将为 0,1,2,3....T999，具体取决于父雇主标签中数据标签的数量.请参阅下面的进一步示例
In the body tag, I'd like to group the data first by the scheme-code and inside the code, group the data by the emp-code in that scheme and then by the data(pin, empr-contr,empyee-contr...) having the empr-code. The serial-no(int) for each data tag will be 0,1,2,3....T999 depending on the number of data tags in the parent employer tag. Please see further example below
<scheme>
<code>10050</code>
[...]
<employer>
<empr-code>PR0000615630</empr-code>
<data>
<serial-no>1</serial-no>
<pin>PEN100144364216</pin>
<employer-contribution>10945.19</employer-contribution>
<employee-contribution>13681.49</employee-contribution>
<voluntary-contribution>0.00</voluntary-contribution>
<total>32218.47</total>
</data>
<data>
<serial-no>2</serial-no>
<pin>PEN100453089112</pin>
<employer-contribution>14319.32</employer-contribution>
<employee-contribution>17899.15/employee-contribution>
<voluntary-contribution>0.00</voluntary-contribution>
<total>32218.47</total>
</data>
<data>
<serial-no>T9999</serial-no>
<pin>PEN200742682512</pin>
<employer-contribution>13116.33</employer-contribution>
<employee-contribution>16395.41</employee-contribution>
<voluntary-contribution>0.00</voluntary-contribution>
<total>29511.74</total>
</data>
</employer>
[...]
</scheme>
如何使用 XMLDocument 或 XMLWriter 生成它
How can I generate it using XMLDocument or XMLWriter
推荐答案
试试下面的 xml linq.我将您的输入文件放入一个文本文件中，然后读入 DataTable.然后从表创建 XML :
Try following xml linq. I put your input file into a text file and then read into DataTable. Then create XML from table :
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Xml;
using System.Xml.Linq;
using System.Data;
using System.IO;
namespace ConsoleApplication1
{
class Program
{
const string INPUT_FILENAME = @"c:\temp\test.txt";
const string OUTPUT_FILENAME = @"c:\temp\test.xml";
static DataTable dt = new DataTable();
static XDocument doc;
static void Main(string[] args)
{
ReadData(INPUT_FILENAME);
dt = dt.AsEnumerable()
.OrderBy(x => x.Field<string>("scheme-code"))
.ThenBy(x => x.Field<string>("emp-code"))
.ThenBy(x => x.Field<string>("pin"))
.CopyToDataTable();
CreateXml();
doc.Save(OUTPUT_FILENAME);
}
static void ReadData(string filename)
{
int rowNumber = 0;
string line = "";
StreamReader reader = new StreamReader(INPUT_FILENAME);
while ((line = reader.ReadLine()) != null)
{
string[] splitData = line.Split(new char[] { ' ' }, StringSplitOptions.RemoveEmptyEntries).ToArray();
if (++rowNumber == 1)
{
for (int i = 0; i < splitData.Length; i++)
{
if (i < 3)
{
dt.Columns.Add(splitData[i], typeof(string));
}
else
{
dt.Columns.Add(splitData[i], typeof(decimal));
}
}
}
else
{
DataRow newRow = dt.Rows.Add();
for (int i = 0; i < splitData.Length; i++)
{
if (i < 3)
{
newRow[i] = splitData[i];
}
else
{
newRow[i] = decimal.Parse(splitData[i]);
}
}
}
}
reader.Close();
}
static void CreateXml()
{
string xmlns_rmas = "value here";
string xmlns_xsi = "value here";
string xmlns_noNamespaceSchemaLocation = "value here";
string xmlIdentFormat =
"<?xml version='1.0' encoding='UTF-8'?>" +
"<return" +
" xmlns:rmas=\"{0}\"" +
" xmlns:xsi=\"{1}\"" +
" xsi:noNamespaceSchemaLocation=\"{2}\">" +
"</return>";
string xmlIdent = string.Format(xmlIdentFormat, xmlns_rmas, xmlns_xsi, xmlns_noNamespaceSchemaLocation);
doc = XDocument.Parse(xmlIdent);
XElement _return = doc.Root;
string returnCode = "";
string returnDesc = "";
DateTime date = DateTime.Now;
string operatorCode = "";
XElement header = new XElement("header", new object[] {
new XElement("return-code", returnCode),
new XElement("return-desc", returnDesc),
new XElement("as-at-date", date),
new XElement("operator-code", operatorCode)
});
_return.Add(header);
XElement body = new XElement("body");
_return.Add(body);
foreach(var schemeGroup in dt.AsEnumerable().GroupBy(x => x.Field<string>("scheme-code")))
{
XElement scheme = new XElement("scheme");
body.Add(scheme);
XElement code = new XElement("code", schemeGroup.Key);
scheme.Add(code);
foreach(var empCodeGroup in schemeGroup.GroupBy(y => y.Field<string>("emp-code")))
{
XElement employer = new XElement("employer");
scheme.Add(employer);
int serialNumber = 0;
foreach(var pinGroup in empCodeGroup.GroupBy(y => y.Field<string>("pin")))
{
if (serialNumber == 0)
{
XElement emprCode = new XElement("empr-code", empCodeGroup.Key);
employer.Add(emprCode);
}
foreach (DataRow row in pinGroup)
{
XElement data = new XElement("data");
employer.Add(data);
if ((empCodeGroup.Count() > 1) && (serialNumber == empCodeGroup.Count() - 1))
{
data.Add(new XElement("serial-no", "T999"));
}
else
{
data.Add(new XElement("serial-no", serialNumber));
}
data.Add(new XElement("pin", pinGroup.Key));
data.Add(new XElement("employer-contribution", row.Field<decimal>("empr-contr")));
data.Add(new XElement("employee-contribution", row.Field<decimal>("empyee-contr")));
data.Add(new XElement("voluntary-contribution", row.Field<decimal>("total-vol-cont")));
data.Add(new XElement("total-contribution", row.Field<decimal>("total")));
serialNumber++;
}
}
}
}
}
}
}
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