XStream 不同字段的相同类(Map.class)的不同别名 [英] XStream different alias for same class (Map.class) for different fields

问题描述

我正在使用 XStream 来转换具有 java.util.Map 类型字段的 Java 类.我有一个 java.util.Map 转换器，它将 Map 的键显示为 xml 元素，将 map 的值显示为 xml 元素的值.我已经使用 registerConverter 方法注册了转换器.当我执行编组时，我得到以下输出.

I am using XStream to convert a Java class which has fields of the type java.util.Map. I have a converter for java.util.Map which displays the key of the Map as an xml element and the value of the map as the value for the xml element. I have registered the converter using registerConverter method. When I perform the marshalling, I get the following output.

<cart account_id="123" shift_id="456" account_postings_id="641">
  <supervisor_id>555</supervisor_id>
  <payments>
    <map sequence="1">
      <amount>123.45</amount>
      <billing_method>12345</billing_method>
      <form>card</form>
      <delivery_mode>Q</delivery_mode>
    </map>
    <map sequence="2">
      <amount>123.45</amount>
      <person_id>2333</person_id>
      <form>cash</form>
      <delivery_mode>Q</delivery_mode>
     </map>
  </payments>
  <items>
    <map sequence="3">
      <amount>1.00</amount>
      <type>pay_toll</type>
      <toll_id>1234</toll_id>
    </map>
  </items>
</cart>

我想根据类中的字段名称使用不同的标签，而不是出现地图标签.例如，Payments 列表将具有标签名称支付，而 Items 列表将具有每个 Map 元素的标签名称项目.

Instead of the map tags appearing, I would want to use different tags based on the field name in the class. For example, the Payments list will have tag name payment and the Items list will have a tag name item for each Map element.

如何根据同一个类中的字段动态设置别名?

How do we dynamically set alias based on field in the same class?

-阿南德

推荐答案

我使用 XStream 来创建原子提要报告.内容中的条目可以是不同的对象类，我想动态地使用类名.这是我的解决方案.我创建了一个 ObjectContentConverter 并传递了 XStream，然后使用 xstream.aliasField() 和 getClass().getSimpleName().>

I used XStream to create atom feed reports. Entries in the contents can be of different object classes and I wanted to use the class name dynamically. Here is my solution. I created a ObjectContentConverter and passed the XStream on, and then use xstream.aliasField() with getClass().getSimpleName().

private class ObjectContentConverter implements Converter {
    XStream xStream;

    private ObjectContentConverter(XStream xStream) {
        this.xStream = xStream;
    }

    @Override
    public void marshal(Object source, HierarchicalStreamWriter writer, MarshallingContext context) {
        String className = WordUtils.uncapitalize(source.getClass().getSimpleName());
        xStream.aliasField(className, Content.class, "objectContent");
        xStream.marshal(source, writer);
    }

    @Override
    public Object unmarshal(HierarchicalStreamReader reader, UnmarshallingContext context) {
        return null;  //To change body of implemented methods use File | Settings | File Templates.
    }

    @Override
    public boolean canConvert(Class type) {
        return true;  //To change body of implemented methods use File | Settings | File Templates.
    }
}

xStream.registerLocalConverter(Content.class, "objectContent", new ObjectContentConverter(xStream));

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