如何计算具有相同属性值的元素 [英] How to count elements with same attribute value
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问题描述
我确信这是一个简单的方法,但我只是不为树只见树木.
I'm sure this is an easy one but i'm just not to see the wood for the trees.
我有一个如下所示的 XML:
I'm having an XML that look like this:
<root>
<profil>
<e1 a="2">1</e1>
<m1 a="3">1</m1>
<e2 a="4">1</e2>
<m2 a="5">1</m2>
</profil>
<profil>
<e1 a="5">1</e1>
<m1 a="3">1</m1>
<e2 a="4">1</e2>
<m2 a="4">1</m2>
</profil>
<profil>
<e1 a="7">1</e1>
<m1 a="7">1</m1>
<e2 a="4">1</e2>
<m2 a="2">1</m2>
</profil>
</root>
现在我想知道每个/profil 有多少/m*/@a 等于 e*/@a.所以我想出了以下 XSLT:
Now I want to know how many /m*/@a are equal to e*/@a per /profil. So I came up with the following XSLT:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:template match="*">
<xsl:element name="root">
<xsl:for-each select="/root/profil">
<xsl:element name="count">
<xsl:value-of select="count(*[contains(name(), 'm') and ./@a = //*[contains(name(),'e')]/@a])"/>
</xsl:element>
</xsl:for-each>
</xsl:element>
</xsl:template>
</xsl:stylesheet>
但结果是错误的:
<root>
<count>1</count>
<count>1</count>
<count>2</count>
</root>
应该是
<root>
<count>0</count>
<count>1</count>
<count>1</count>
</root>
有人建议我做错什么吗?
Does anyone has a suggestion what I'm doing wrong?
推荐答案
将 XPath 替换为正确的 XPath,即:
Replace the XPath with the correct one, which is:
<xsl:value-of select="count(*[substring(name(),1,1)='m'
and ./@a = ../*[substring(name(),1,1)='e']/@a])"/>
我使用 substring
来匹配第一个属性字符,而不是 contains
匹配字符串中的任何字符.
I've used substring
to match the first attribute character in place of contains
which matches any character in a string.
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