根据属性和节点值提取节点 [英] Extract nodes based on attribute and node values
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问题描述
对于下面的 XML，我试图根据属性和节点值提取节点.
For the below XML, I'm trying to extract the nodes based on attribute and node values.
基于属性 class=pass 和 h1 包含 ('objectives')，我试图提取以下输出.
Based on attribute class=pass and h1 contains ('objectives'), I'm trying to extract the below output.
objectives"是节点值字符串1个任务目标"的一部分
"objectives" is a part of the node value string "1 task objectives"
1 任务目标对象 1对象2
1 task objectives object1 object2
<body>
<article>
<body>
<section>
<h1>intro1</h1>
<region>introd1</region>
<region>introd2</region>
</section>
<section>
<h1 class="pass">1 task objectives</h1>
<region>object1</region>
<region>object2</region>
</section>
</body>
</article>
</body>
下面是我正在尝试的 XPath 表达式.但是，这并没有给出任何输出.你能指出我做错了什么吗?
Below is the XPath expression I am trying. However, this is not giving any output. Can you please point out what I am doing wrong?
//body//section//h1[contains(.,'objectives') and @class="pass"]/*/text()
谢谢&问候，西马克
Thanks & Regards, Simak
推荐答案
试试这个:
//body/section/h1[contains(.,'objectives') and @class='pass']/..//text()
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