如何使用 xslt 将 json 转换为 xml [英] How to convert json to xml using xslt
问题描述
您将如何将 JSON 转换为 XML?
How would you convert JSON to XML?
考虑:
<sampleTag>
{
"Order": {
"InvestmentAccount": { "AccountNumber": "10" },
"Parcel": {
"Limit": "0",
"ExpiryDate": "1900-01-01T00:00:00",
"Asset": [
{
"Open": "25.15",
"High": "25.15",
"Low": "25.11",
"Close": "25.87"
}
{
"Open": "25.15",
"High": "25.15",
"Low": "25.11",
"Close": "25.87"
}]
},
"OrderDate": "2012-10-11T21:46:03.6489906+11:00",
}
}
</sampleTag>
转换后的文档如下:
<Order>
<InvestmentAccount>
<AccountNumber>10</AccountNumber>
</InvestmentAccount>
<Parcel>
<Limit>0</Limit>
<ExpiryDate>1900-01-01T00:00:00</ExpiryDate>
<Asset>
<Open>25.15</Open>
<High>25.15</High>
<Low>25.11</Low>
<Close>25.87</Close>
</Asset>
<Asset>
<Open>25.15</Open>
<High>25.15</High>
<Low>25.11</Low>
<Close>25.87</Close>
</Asset>
</Parcel>
<OrderDate>2012-10-11T21:46:03.6489906+11:00</OrderDate>
</Order>
推荐答案
我在 JSON 解析方面的工作并未涵盖完整的 JSON 语法.
My work on JSON parsing doesn't cover the full JSON grammar.
将任何 JSON 文档翻译"为 XML 文档的任务没有解决方案.有一些 JSON 结构,如果不定义额外的约定和引入额外的元素,就无法将其转换为 XML——因此最终的 XML 结构不是原始 JSON 对象的真实自然表示.
And the task of "translating" any JSON document to an XML document doesn't have a solution. There are JSON constructs, which cannot be translated to XML without defining additional conventions and introducing additional elements -- so the final XML structure isn't a true and natural representation of the original JSON object.
在 XSLT 3.0 中有一个函数可以解析任何 JSON 对象——parse-json() -- 到 map -- XSLT 3.0 中引入的一种新数据类型.在这里阅读:http://www.w3.org/TR/xslt-30/#json一个>
In XSLT 3.0 there is a function to parse any JSON object -- parse-json() -- to a map -- a new data type introduced in XSLT 3.0. Read about this here: http://www.w3.org/TR/xslt-30/#json
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