XSLT 将多个节点组合成单个节点 [英] XSLT combine multiple nodes into single node
问题描述
<RowSet>
<Row>
<Location_Long_Desc>Sydney Office</Location_Long_Desc>
<Location_Code>SYDNEY</Location_Code>
<Daypart_Long_Desc>Peak Night</Daypart_Long_Desc>
<Daypart_Code>PEANIG</Daypart_Code>
<W_20050703_Dlr>30849.3</W_20050703_Dlr>
<W_20050703_Spots>9</W_20050703_Spots>
<W_20050710_Dlr>16.35</W_20050710_Dlr>
<W_20050710_Spots>19</W_20050710_Spots>
</Row>
</RowSet>
所以,我现在有了这个 XML,我需要将 W_ 节点转换为新的单个节点.使用这个 XSL
So, I have this XML now what I need to convert the W_ nodes into a new single node. Using this XSL
<?xml version="1.0"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" indent="yes"/>
<xsl:template match="node()">
<xsl:copy>
<xsl:apply-templates select="node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="*">
<xsl:variable name="tmp" select="local-name()"/>
<xsl:choose>
<xsl:when test="starts-with($tmp, 'W_') and ends-with($tmp, '_Dlr')">
<xsl:if test="text() != ''">
<xsl:element name="Expenditure">
<xsl:element name="Period">
<xsl:value-of select="substring($tmp,3,8)"/>
</xsl:element>
<xsl:element name="Value">
<xsl:apply-templates select="node()"/>
</xsl:element>
<xsl:element name="Spots">
<xsl:apply-templates select="//RowSet/Row/W_20050703_Spots/text()"/>
</xsl:element>
</xsl:element>
</xsl:if>
</xsl:when>
<xsl:otherwise>
<xsl:element name="{$tmp}">
<xsl:apply-templates select="node()"/>
</xsl:element>
</xsl:otherwise>
</xsl:choose>
</xsl:template>
</xsl:stylesheet>
我几乎可以到达那里,但我有几个问题.
I can almost get there but I have a couple of issues.
- 我需要将 W_????????Dlr 和 W??????????_Spots 组合成一个单独的节点,但
- 我不知道如何在 xpath 语句中使用变量,或者我可能离我应该去的地方很远.
- I need to combine the W_????????Dlr and W????????_Spots into a individual nodes but
- I can't work out how to use a variable in an xpath statement, or maybe I'm miles off where I should be.
再说一次,我还在掌握这一切,所以请保持温柔;-)
Again, I'm still getting to grips with it all, so please be gentle ;-)
TIA
02/12/2010 12:00
02/12/2010 12:00
好的,
再问一个问题,根据数据库级别的切换(我完全忘记了),Spots 节点可能存在也可能不存在.
Just a little further question, depending on a database level switch (which I forgot all about), the Spots node may or may not exist.
所以我仍然需要输出,尽管它不应该输出到后续兄弟节点不是有效的 _spots 节点的后续兄弟节点调用.
So I still need to output though it shouldn't to the following-sibling call where the following-sibling isn't a valid _spots node.
示例:
<RowSet>
<Row>
<Location_Long_Desc>Sydney Office</Location_Long_Desc>
<Location_Code>SYDNEY</Location_Code>
<Daypart_Long_Desc>Peak Night</Daypart_Long_Desc>
<Daypart_Code>PEANIG</Daypart_Code>
<W_20050703_Dlr>30849.3</W_20050703_Dlr>
<W_20050710_Dlr>16.35</W_20050710_Dlr>
</Row>
</RowSet>
请注意,我通过 Oracle 包调用所有这些
Just so you know, I'm calling all this via an Oracle package
-- get the query context;
v_qryctx := dbms_xmlgen.newcontext(in_sql_query);
dbms_xmlgen.setnullhandling(v_qryctx, 2);
dbms_xmlgen.setrowsettag(v_qryctx, 'RowSet');
dbms_xmlgen.setrowtag(v_qryctx, 'Row');
IF in_export_type = cnst_export_booking
THEN
dbms_xmlgen.setxslt(v_qryctx, v_booking_export_xsl);
ELSIF in_export_type = cnst_export_expenditure
THEN
dbms_xmlgen.setxslt(v_qryctx, v_expenditure_export_xsl);
END IF;
推荐答案
这种转变:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="node()|@*">
<xsl:copy>
<xsl:apply-templates select="node()|@*"/>
</xsl:copy>
</xsl:template>
<xsl:template match=
"*[starts-with(name(),'W_')
and
substring-after(substring-after(name(),'_'),'_')='Dlr'
and
text()
]">
<Expenditure>
<Period>
<xsl:value-of select="substring(name(),3,8)"/>
</Period>
<Value>
<xsl:apply-templates/>
</Value>
<xsl:apply-templates mode="extract" select=
"following-sibling::*[1]
[starts-with(name(),'W_')
and
substring-after(substring-after(name(),'_'),'_')='Spots'
]
"/>
</Expenditure>
</xsl:template>
<xsl:template mode="extract" match=
"*[starts-with(name(),'W_')
and
substring-after(substring-after(name(),'_'),'_')='Spots'
]
">
<Spots><xsl:value-of select="."/></Spots>
</xsl:template>
<xsl:template match=
"*[starts-with(name(),'W_')
and
substring-after(substring-after(name(),'_'),'_')='Spots'
]
"/>
</xsl:stylesheet>
应用于提供的源 XML 文档时:
<RowSet>
<Row>
<Location_Long_Desc>Sydney Office</Location_Long_Desc>
<Location_Code>SYDNEY</Location_Code>
<Daypart_Long_Desc>Peak Night</Daypart_Long_Desc>
<Daypart_Code>PEANIG</Daypart_Code>
<W_20050703_Dlr>30849.3</W_20050703_Dlr>
<W_20050703_Spots>9</W_20050703_Spots>
<W_20050710_Dlr>16.35</W_20050710_Dlr>
<W_20050710_Spots>19</W_20050710_Spots>
</Row>
</RowSet>
产生想要的、正确的结果:
<RowSet>
<Row>
<Location_Long_Desc>Sydney Office</Location_Long_Desc>
<Location_Code>SYDNEY</Location_Code>
<Daypart_Long_Desc>Peak Night</Daypart_Long_Desc>
<Daypart_Code>PEANIG</Daypart_Code>
<Expenditure>
<Period>20050703</Period>
<Value>30849.3</Value>
<Spots>9</Spots>
</Expenditure>
<Expenditure>
<Period>20050710</Period>
<Value>16.35</Value>
<Spots>19</Spots>
</Expenditure>
</Row>
</RowSet>
当应用于第二个提供的 XML 文档时,OP 在更新中请求:
when applied on the second provided XML document, requested in an Update by the OP:
<RowSet>
<Row>
<Location_Long_Desc>Sydney Office</Location_Long_Desc>
<Location_Code>SYDNEY</Location_Code>
<Daypart_Long_Desc>Peak Night</Daypart_Long_Desc>
<Daypart_Code>PEANIG</Daypart_Code>
<W_20050703_Dlr>30849.3</W_20050703_Dlr>
<W_20050710_Dlr>16.35</W_20050710_Dlr>
<W_20050710_Spots>19</W_20050710_Spots>
</Row>
</RowSet>
又是想要的正确结果(如果直接兄弟不是 W_nnnnnnnn_Spots
,则不会生成
元素)是制作:
again the wanted, correct result (No <Spot>
element is generated if the immediate sibling isn't a W_nnnnnnnn_Spots
) is produced:
<RowSet>
<Row>
<Location_Long_Desc>Sydney Office</Location_Long_Desc>
<Location_Code>SYDNEY</Location_Code>
<Daypart_Long_Desc>Peak Night</Daypart_Long_Desc>
<Daypart_Code>PEANIG</Daypart_Code>
<Expenditure>
<Period>20050703</Period>
<Value>30849.3</Value>
</Expenditure>
<Expenditure>
<Period>20050710</Period>
<Value>16.35</Value>
<Spots>19</Spots>
</Expenditure>
</Row>
</RowSet>
请注意:
使用身份规则按原样"复制任何节点.
The use of the identity rule to copy any node "as-is".
覆盖标识模板仅适用于 W_nnnnnnnn_Dlr
元素.
使用空模板覆盖身份模板 匹配 W_nnnnnnnn_Spots
元素.
标准 XPath 函数的使用:name()
, starts-with()
和 substring-after()
函数ends-with()
仅在 XPath 2.0 (XSLT 2.0) 中可用,在此 XSLT 1.0 解决方案中未使用.
The function ends-with()
is only available in XPath 2.0 (XSLT 2.0) and isn't used in this XSLT 1.0 solution.
这篇关于XSLT 将多个节点组合成单个节点的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!