XSL msxsl:node-set 问题 [英] XSL msxsl:node-set problem

问题描述

请大家帮帮我.我只是想声明一个简单的结果树片段并对其进行迭代.

Please help me out guys. I'm just trying to declare a simple result tree fragment and iterate over it.

...

<xsl:variable name="rtf">
  <item-list>
    <item id="1">one</item>
    <item id="2">two</item>
    <item id="3">three</item>
    <item id="4">four</item>
  </item-list>
</xsl:variable>

<xsl:for-each select="msxsl:node-set($rtf)/item-list/item">
  <xsl:value-of select="@id"/>
</xsl:for-each>

...

我完全误解了这是如何工作的吗?

Am I completely mistaken about how this works?

我正在使用 .NET XslCompiledTransform 并具有正确的 msxsl 命名空间声明 - xmlns:msxsl="urn:schemas-microsoft-com:xslt"

I'm using .NET XslCompiledTransform and have the correct msxsl namespace declarations - xmlns:msxsl="urn:schemas-microsoft-com:xslt"

转换执行得很好 - 问题是没有输出任何内容

The transformating executes fine - the problem is that nothing is output

推荐答案

我怀疑您在样式表中声明了一个默认命名空间.这将有效地将 和 元素放入命名空间中.要使用 XPath 1.0 选择命名空间限定的元素，您必须始终在表达式中使用前缀.

My suspicion is that you have a default namespace declared in your stylesheet. That would effectively place the <item-list> and <item> elements into a namespace. To select namespace-qualified elements using XPath 1.0, you must always use a prefix in the expression.

因此，如果您的样式表顶部有这样的内容:

So if you have something like this at the top of your stylesheet:

<xsl:stylesheet xmlns="http://example.com"...>

然后你还需要添加:

<xsl:stylesheet xmlns="http://example.com" xmlns:x="http://example.com"...>

然后在 XPath 表达式中使用x"前缀:

And then use the "x" prefix in your XPath expression:

<xsl:for-each select="msxsl:node-set($rtf)/x:item-list/x:item">
  <xsl:value-of select="@id"/>
</xsl:for-each>

让我知道这是否奏效.我只是在这里猜测.

Let me know if that did the trick. I'm only speculating here.

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