分配给 <xsl:variable>解除后 [英] Assign to &lt;xsl:variable&gt; after thedecleration

问题描述

我正在使用以下方法为变量赋值.

I am using the below way to assign value to a variable.

<xsl:variable name="NewValue">
  <xsl:value-of select="normalize-space(//root/id/amount)"/>
</xsl:variable>

赋值后，我想为同一个变量分配新值.像这样:-

After the assignment I want to assign new value to the same variable. Like this:-

<xsl:variable name="NewValue" select="normalize-space(//root/id/amountnew)">

有什么办法吗?

这是我拥有的 XML 示例:

Here the sample of XML that I have:

<VolLien>
  <Vest_DocType>SDD</Vest_DocType>
  <Vest_Instrument>395072</Vest_Instrument>
  <Vest_OfOfficialEntity>eee</Vest_OfOfficialEntity>
  <Vest_RecDate>12/24/2009</Vest_RecDate>
  <Vest_Grantee1>abc dd</Vest_Grantee1>
  <Vest_Grantor1>sss</Vest_Grantor1>
  <Vest_RejectCode />
  <Vest_RejectReason /> 
  <Vest_ImageNum> </Vest_ImageNum>
</VolLien>

我的问题是我需要获取特定的最新(比如SDD)然后我需要在任何日期搜索xml在 之前(相同的 SDD).

My problem is I need to get latest <Vest_RecDate> of particular <Vest_DocType>(say SDD) And then I need to search across the xml any date which is before <Vest_RecDate> of this(same SDD).

如果然后单独提出该特定部分()并再次更新.如果我可以重新分配，我会定位节点并获取与之相关的值.现在我正在使用另一个循环来执行此操作.如果有什么，我可以避免 extrs 循环.

If then raise that particular section(<VolLien>) alone and again latest. If I could have reassignment I would position of the node and get the values associated to that. Now I am doing this using another loop. If something is there I can avoid extrs loops.

推荐答案

没有.XSLT 变量是只读的.它们不能被多次分配.

No. XSLT variables are read-only. They cannot be assigned multiple times.

XSLT 不是像 PHP 这样的命令式编程语言.重新分配变量既不可能也没有必要.

XSLT is not an imperative programming language like, say, PHP. Reassigning variables is both impossible and unnecessary.

根据您的评论:

我的问题是我需要获取最新的特定 (比如 SDD)，然后我需要在 xml 中搜索 <之前的任何日期/code> 这个(相同的 SDD).

My problem is I need to get latest of particular <Vest_DocType> (say SDD) and then I need to search across the xml any date which is before <Vest_RecDate> of this (same SDD).

这是可以为您执行此操作的 XSLT 代码段:

here is an XSLT snippet that can do this for you:

<!-- a key to retrieve all <VolLien> nodes of a particular DocType -->
<xsl:key name="VolLien-by-DocType" match="VolLien" use="Vest_DocType" />

<xsl:template match="/">
  <xsl:call-template name="latest-VolLien">
    <xsl:with-param name="DocType" select="'SDD'" />
  </xsl:call-template>
</xsl:template>

<!-- this template processes specified <VolLien> nodes in the right order -->
<xsl:template name="latest-VolLien">
  <xsl:param name="DocType" select="''" />

  <xsl:for-each select="key('VolLien-by-DocType', $DocType)">
    <!-- sorting is a little complicated because you 
         use dd/mm/yyyy instead of yyyymmdd -->
    <xsl:sort 
      select="
        number(substring(Vest_RecDate, 7, 4)) + 
        number(substring(Vest_RecDate, 4, 2)) + 
        number(substring(Vest_RecDate, 1, 2))
      "
      data-type="number"
    />
    <!-- do something with last <VolLien> (in date order) -->
    <xsl:if test="position() = last()">
      <xsl:apply-templates select="." />
    </xsl:if>
  </xsl:for-each>
</xsl:template>

<xsl:template match="VolLien">
  <!-- this template will actually process the nodes,
       do whatever you want here -->
</xsl:template>

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