Ruby 中的 YAML 解析:如何仅获取某种类型的元素? [英] YAML parsing in Ruby: How to get only a certain type of elements?

问题描述

我有以下 YAML:

- name: List of monkeys
- author: Nicolas Raoul
- version: 2
- monkey: 
   - name: Chee-Chee
   - age: 2
- monkey:
   - name: Curious George
   - age: 6
   - food: bananas
- monkey:
   - name: Mojo
   - food: peanuts

在 Ruby 中，如何获取猴子?
序言中元数据参数的数量(姓名、作者、...)是可变的.

In Ruby, how to get the monkeys?
The number of metadata parameters in the preamble (name, author, ...) is variable.

它会返回如下内容:

[{"monkey"=>[{"name"=>"Chee-Chee"}, {"age"=>2}]}, {"monkey"=>[{"name"=>"Curious George"}, {"age"=>6}, {"food"=>"bananas"}]}, {"monkey"=>[{"name"=>"Mojo"}, {"food"=>"peanuts"}]}]

在 XML/XPath 中，我会简单地编写 /monkey，但是 YAML/Ruby 的语法是什么?

In XML/XPath I would simply write /monkey, but what is the syntax with YAML/Ruby ?

注意:我不想创建一个包含所有猴子作为子项的monkeys节点，因为有很多猴子，客户端会编辑文件添加更多，所以我想让文件非常简单.我是 YAML 的新手，所以可能需要一个更好的组织，但简洁是最重要的，特别是我不想增加子级别的数量.

Note: I don't want to create a monkeys node containing all monkeys as sub-items, because there are many monkeys and the clients will edit the file to add more, so I want to keep the file really simple. I am new to YAML so a better organization might be needed, but brevity is paramount, in particular I don't want to increase the number of sub-levels.

推荐答案

您可以使用 Enumerator 的 #select 方法只返回集合中的猴子.如果您在一个名为 your_yaml 的变量中解析了 YAML 对象，则此代码将返回您所要求的内容:

You can use Enumerator's #select method to return just the monkeys from your collection. If you have your parsed YAML object in a variable called your_yaml, this code would return what you are asking for:

your_yaml.select { |item|item['monkey'] }

您可能不需要第二级中的连字符.如果你改变这个...

You probably don't need the hyphens in the second level. If you change this...

- monkey: 
   - name: Chee-Chee
   - age: 2

进入这个:

- monkey: 
    name: Chee-Chee
    age: 2

猴子的属性将是一个散列，而不是一个散列数组.我想这对你更有用.

The monkey's properties will be a hash, instead of an array of hashes. I'd imagine this is more useful to you.

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