如何打印出对象的值 [英] How to print out a value of object

问题描述

我想知道如何获取对象的值.我正在使用 Yii 框架来实现下载功能.如何从前端传递参数

I want to know how to get a value of object. I am using Yii framework for imeplement a download function. How to pass a parameter from frontend

我打印了一个对象，但我不知道如何从这个对象中获取值.

I printed out a object, but I don't know how to get a value from this object.

Array
(
    [file] => CUploadedFile Object
        (
            [_name:CUploadedFile:private] => 23602414.pdf
            [_tempName:CUploadedFile:private] => D:\wamp\tmp\php8780.tmp
            [_type:CUploadedFile:private] => application/pdf
            [_size:CUploadedFile:private] => 181004
            [_error:CUploadedFile:private] => 0
            [_e:CComponent:private] => 
            [_m:CComponent:private] => 
        )

    [layout] => //layouts/column1
    [menu] => Array
        (
        )

    [breadcrumbs] => Array
        (
        )

    [defaultAction] => index
    [_widgetStack] => Array
        (
        )

)

我想获取23602414.pdf"，并将其存储到变量中.

I want to get the "23602414.pdf", and store it to a varable.

这是我的代码.

<?php $model=new Upload(); ?>

<?php if(isset($_POST['Upload'])){$model->attributes=$_POST['Upload'];

$this->file=CUploadedFile::getInstance($model,'file');

}?>

<?php echo CHtml::link('Download file',array('/upload/download','id'=>'23602414.pdf')); ?>

我想在那里回显文件名，而不是硬编码为id"=>23602414.pdf".

Instead of hard code as 'id'=>'23602414.pdf', I want to echo the file name in there.

推荐答案

试试这个

<?php $model=new Upload(); ?>

<?php if(isset($_POST['Upload'])){$model->attributes=$_POST['Upload'];

$this->file=CUploadedFile::getInstance($model,'file');

}?>

<?php echo CHtml::link('Download file',array('/upload/download','id'=>$this->file->getName())); ?>

此处的文档https://www.yiiframework.com/doc/api/1.1/CUploadedFile

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