Zend Framework:如何通过指定列的值查找表行? [英] Zend Framework: How to find a table row by the value of a specified column?

问题描述

我正在像快速入门一样实现我的模型指南.

在我的模型中，我试图实现一个 findByToken() 方法.当前的 find() 方法接受一个 $id 参数，但我想通过不同列的值进行查找.

In my model I am trying to implement a findByToken() method. The current find() method accepts an $id parameter, but I want to find by the value of a different column.

//excerpt from the quickstart guide
public function find($id, Default_Model_Guestbook $guestbook)
{
    $result = $this->getDbTable()->find($id);
    if (0 == count($result)) {
        return;
    }
    $row = $result->current();
    $guestbook->setId($row->id)
              ->setEmail($row->email)
              ->setComment($row->comment)
              ->setCreated($row->created);
}

我尝试做这样的事情，但我认为它不起作用:

I tried doing something like this, but I don't think it worked:

$db = $this->getDbTable();
$where = $db->getAdapter()->quoteInto('token = ?', $token);
$result = $db->find($where);

通过指定列的值查找行的正确方法是什么?

What would be the proper way to find a row by the value of a specified column?

推荐答案

$result = $db->fetchAll($where);

或者如果您只想检索一行.

or if you are trying to retrieve only one row.

$result = $db->fetchRow($where);

您也可以使用 Zend_Db_Select 对象，使适配器更加抽象:

You could also use the Zend_Db_Select Object, keeping the adapter a little further abstracted:

$db = $this->getDbTable();
$select = $db->select()->where('token = ?', $token);
$result = $db->fetchAll($select);

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