如何将变量从搜索表单传递给另一个操作? [英] How do I pass variables to another action from a search form?

查看:32
本文介绍了如何将变量从搜索表单传递给另一个操作?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我有两个搜索页面.一种是精简搜索形式,另一种是高级搜索.

I have two search pages. One is a condensed search form the other is an advanced search.

我希望用户在精简页面上输入他们的搜索,并被重定向到包含高级搜索字段的结果页面.

I would like the user to enter their search at on the condensed page and be redirected to the results page which contains the advanced search fields.

我目前遇到的两个问题是:

The two issues I currently have are:

  • 如何重定向?
  • 当字段留空时,最佳做法是什么?

目前,我一直在回溯索引以获取前两个搜索字段

Currently, I keep looking back to the index to get the first two search fields

精简搜索

public function indexAction()
{
     $dbAdapter = $this->getServiceLocator()->get('Zend\Db\Adapter\Adapter');
     $form = new HomeSearchForm($dbAdapter);        
     $request = $this->getRequest();   
     if ($request->isPost()) {    
         $homeSearch = new HomeSearch();          
         $form->setInputFilter($homeSearch->getInputFilter());                
         $form->setData($request->getPost());            
         if ($form->isValid()) { 
             $homeSearch->exchangeArray($form->getData());

             if($homeSearch->search_zip == null)
             {
              $homeSearch->search_zip = 'null';
             }

             if($homeSearch->industry_name == null)
             {
              $homeSearch->industry_name = 'null';
             }


           return $this->redirect()->toRoute('home/results',array(
                'zip'=>$homeSearch->search_zip ,
                'industry'=>$homeSearch->industry_name,
           ));

         }
          else {
              echo "Error";
          }           
    }
      return array('form' => $form);
}

结果/高级搜索

public function resultsAction()
{        
     $search_zip      = $this->params()->fromPost('zip');
     $search_industry = $this->params()->fromRoute('industry');
     $search_language      = $this->params()->fromPost('language');
     $search_gender      = $this->params()->fromRoute('gender');
     $search_name      = $this->params()->fromRoute('name');

     echo var_dump($search_zip);
      echo var_dump($search_industry);
      echo var_dump($search_gender);
     echo var_dump($search_name);

     $dbAdapter = $this->getServiceLocator()->get('Zend\Db\Adapter\Adapter'); 
     $proSearch = new SearchQuery($dbAdapter);
     $form = new SearchForm($dbAdapter); 

     $request = $this->getRequest();   
     if ($request->isPost()) {
         echo 'i post';
         $search = new MainSearch();          
         $form->setInputFilter($search->getInputFilter());                
         $form->setData($request->getPost());  

         if ($form->isValid()) { 
             $search->exchangeArray($form->getData());
             if($search->search_zip == null)
             {
              $search->search_zip = 'null';
             }

             if($search->industry_name == null)
             {
              $search->industry_name = 'null';
             }

             if($search->language_name == null)
             {
              $search->language_name = 'null';
             }

             if($search->pro_gender == null)
             {
              $search->pro_gender = 'null';
             }


         return $this->redirect()->toRoute('home/results', array(
            'action'     => 'results',
            'zip'   => $search->search_zip,
            'industry'   => $search->industry_name,
            'language'   => $search->language_name,
            'gender'   => $search->pro_gender,
            'name'   => $search->pro_name,
          )); 

         }  
     }

      return array(
          'form' => $form,
          'pros' => $proSearch->proSearch($search_zip,$search_industry,$search_language,$search_gender,,$search_name),
              );
}

更新

我能够使用我在下面发布的方法进行搜索.但是,我仍然无法获取要在 url 中发布的参数(我可以使用此代码获取我想要的 url,但是我无法应用过滤器并将字段绑定到表单 $this->form->setAttributes(array('method' => 'GET'));

I am able to get the search to work with the method I have posted below. However I still cannot get the parameters to post in the url (I am able to get the url I want using this code however I have trouble applying the filter and binding the fields to the form $this->form->setAttributes(array('method' => 'GET'));

Post Redirect 插件不是用来阻止用户返回的吗?阅读手册后,我不确定如何使用此插件?我不确定为什么没有使用以下代码设置该段,我过去曾使用过它.

Isn't the Post Redirect plugin used to prevent users from going back? After reading the manual I am not sure how I go about using this plugin? I'm not sure why the segment is not setting with the below code, I have used this in the past.

'search_zip'=> $this->search_zip 

模块配置

            'results' => array(
                'type' => 'segment',
                'options' => array(
                    'route' => 'results[/:search_zip][/:search_industry][/:language][/:gender][/:designation][/:name]',
                    'defaults' => array(
                        'controller' => 'Application\Controller\Index',
                        'action'     => 'results',

结果操作

  public function resultsAction()
    {   
         $dbAdapter = $this->getServiceLocator()->get('Zend\Db\Adapter\Adapter'); 
         $proSearch = new SearchQuery($dbAdapter);
         $request = $this->getRequest();   
         $form = new SearchForm($dbAdapter);  
         if ($request->isPost()) {
             $search = new MainSearch();          
             $form->setInputFilter($search->getInputFilter());                
             $form->setData($request->getPost());  
             if ($form->isValid()) { 
                 $search->exchangeArray($form->getData());
                 $search_zip = $search->search_zip;
                 $search_industry = $search->search_industry;
                 $search_language = $search->search_language;
                 $search_gender = $search->search_gender;
                 $search_designation = $search->search_designation;
                 $search_name = $search->search_name;
             }  
         }

          return array(
              'form' => $form,
              'pros' => $proSearch->proSearch($search_zip,$search_industry,$search_language,$search_gender,$search_designation,$search_name),
                  );

    }

结果视图

//Search Index

 $title = 'Search';
 $this->headTitle($title);
 ?>
 <h1><?php echo $this->escapeHtml($title); ?></h1>
 <?php
    $form->setAttribute('action', $this->url(
     'home/results',
     array(
         'action' => 'results',
         'search_zip'=> $this->search_zip

     )
 ));
 //$form->setAttributes(array('method' => 'GET'));
 $form->prepare();

 echo $this->form()->openTag($form);
 echo $this->formRow($form->get('industry_name'));
 echo $this->formRow($form->get('search_zip'));
 echo '<br>';
 echo $this->formRow($form->get('language_name'));
 echo $this->formRow($form->get('pro_gender'));
 echo '<br>';
 echo $this->formRow($form->get('designation_name'));
 echo $this->formRow($form->get('pro_name'));
 echo $this->formSubmit($form->get('submit'));

 ?>
 <h2>Results</h2>
 <table class="table">
 <tr>
     <th>First Name</th>
     <th>Last Name</th>
     <th>Street Address</th>
     <th>Office Number</th>
     <th>City</th>
     <th>State</th>
     <th>Zip</th>
     <th>&nbsp;</th>
 </tr>
 <?php foreach ($pros as $pro) : ?>
 <tr>
     <td><?php echo $this->escapeHtml($pro->pro_first);?></td>
     <td><?php echo $this->escapeHtml($pro->pro_last);?></td>
     <td><?php echo $this->escapeHtml($pro->pro_street_address);?></td> 
     <td><?php echo $this->escapeHtml($pro->pro_office_number);?></td> 
     <td><?php echo $this->escapeHtml($pro->pro_city);?></td> 
     <td><?php echo $this->escapeHtml($pro->pro_state);?></td> 
     <td><?php echo $this->escapeHtml($pro->pro_zip);?></td> 
 <?php endforeach; ?>
 </table>

推荐答案

我已经重构了您提供的代码以显示我将如何处理该问题.

I've refactored the code you provided to display how I would approach the issue.

仔细研究方法;关键的变化是封装功能.

Study the approach carefully; the key changes are encapsulating the functionality.

先决条件

  • 两种形式都应该POSTresultsAction()
  • 您只需要一种类型"的搜索对象(此处称为 Search)
  • 封装!两种形式都提供结果和搜索,如果您在逻辑上将功能分开,这将使您的代码更容易(阅读和维护)

未经测试,这是您的工作!

Not tested, that's your job!

public function simpleSearchAction()
{
    $form = $this->getSimpleSearchForm();

    return new ViewModel(compact('form'));
}

public function advancedSearchAction()
{
    $form = $this->getAdvancedSearch();

    return new ViewModel(compact('form'));
}

public function resultsAction()
{
    $request = $this->getRequest();
    $form = $this->getAdvancedSearch();
    $results = array();

    if ($request->isPost()) {

        $form->setData($request->getPost());

        if ($form->isValid()) {

            $search = new Search();
            $search->exchangeArray($form->getData());

            // Execute the search and return the results
            $results = $this->search($search);

            // Populate the form with the search data
            $form->bind($search);
        }
    }

    return new ViewModel(array(
        'form'    => $form,
        'results' => $results,
    ));
}

protected function search(Search $search)
{
    // do search here, although this shouldn't be
    // in the controller, rather a service!
    return $yourResults;
}

// This should be injected into the controller
protected function getAdapter();

// Forms should be using the FormElementManager, not
// being created using new
protected function getSimpleSearchForm();

// Same as above
protected function getAdvancedSearch();

考虑

  • 发布重定向插件(如果您想要带有搜索词的漂亮网址)
  • 依赖注入!您错过了 ZF2 的好处,请在服务工厂中创建 DbAdapterForms 并将它们注入到控制器的构造函数中.
  • 服务层 - 移出search 代码将使其可重用,并将控制器 逻辑与业务 逻辑分开.
  • Post Redirect plugin (if you want nice URL's with the search terms)
  • Dependency injection! Your missing out on the benefits of ZF2, create the DbAdapter and Forms in service factories and inject them into the controller's constructor.
  • Service layer - Moving out the search code will make it reusable and separate the controller logic from business logic.

这篇关于如何将变量从搜索表单传递给另一个操作?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆