Python zipfile整个路径在文件中 [英] Python zipfile whole path is in file

问题描述

我使用的是此处的代码 从目录制作 zip 文件.我给函数一个从 GUI 到文件夹的绝对路径.目前，假设路径是 c:\users......，zip 文件夹结构是 users...... .

I'm using the code from here to make a zip file from a directory. I give the function an absolute path to a folder from a GUI. Currently, say the path is c:\users......, the zip folder structure is users...... .

我怎样才能删除绝对路径位并只使用用于 zip 文件的路径的结束文件夹?我知道结果是正确的，因为我描述的是 os.walk 的结果，但我想去掉绝对路径.

How can I remove the absolute path bits and just have the end folder of the path being used for the zip file? I understand that the result is right, because what I'm describing is the result from os.walk but I want to strip out the absolute path.

def zipdir(path, zip):
    for root, dirs, files in os.walk(path):
        for file in files:
            zip.write(os.path.join(root, file))

推荐答案

这样做:

def zipdir(path, zip):
    path = os.path.abspath(path)
    for root, dirs, files in os.walk(path):
        dest_dir = root.replace(os.path.dirname(path), '', 1)
        for file in files:
            zip.write(os.path.join(root, file), arcname=os.path.join(dest_dir, file))

这会将给定的 path 转换为绝对路径，其目录名称用于删除 root 中的前导路径组件.

This converts the given path to an absolute path, the directory name of which is used to remove the leading path component in root.

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